Use IF in a mySQL query [closed]
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Closed 8 years ago.
Improve this questionI'm trying to make a SELECT
where I need to select a specified table by a column wich define the type of subject:
table_buildings
id name location source_type source_id
1 NY Appartament New York 0 NULL
2 Guggenheim Museum Manhattan 1 27
3 MoMA New York 2 3
table_url // source type == 1
id name url
27 Guggenheim Site http://www.guggenheim.org/
table_books // source type == 2
id name pages sample author
3 World Museums 125-127 path/img.jpg John Smith
I don't know if it's possible, but I have some problem to solve it without an IF
statement inside my query because I can find the right table by the sou开发者_开发知识库rce_type
column of table_buildings
does exist soma tecnique to use an IF
inside a SELECT
query?
I'd just join both tables and use COALESCE
for duplicate column names in the joined tables.
SELECT COALESCE(table_url.name, table_books.name) as name, url, pages, sample author FROM table_buildings
LEFT OUTER JOIN table_url ON table_buildings.source_type = 1 AND table_buildings.source_id = table_url.id
LEFT OUTER JOIN table_books ON table_buildings.source_type = 2 AND table_buildings.source_id = table_books .id
I am afraid the only possible way is select from all tables unconditionally. Not a much overhead though.
Just left join as much tables as you need. ones with no corresponding information will just return nulls.
You could UNION
three different SELECT
s that JOIN
to the three tables with WHERE
clauses.
Alternatively, you could join against all three tables in one query and use a CASE
operator to select a column from the appropiate joined table based on source_type
.
you can use "CASE WHEN" in the SELECT.
SELECT
table_buildings.id,
table_buildings.name,
table_buildings.location,
CASE WHEN table_buildings.source_type = 0
THEN ""
ELSE CASE WHEN table_buildings.source_type = 1
THEN table_url.name
ELSE table_books.name
END CASE
END CASE AS source_name
FROM table_buildings
LEFT JOIN table_url
ON table_buildings.source_id = table_url.id
LEFT JOIN table_books
ON table_buildings.source_id = table_books.id
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