Castle ActiveRecord JoinedKey is not set
I am using "Class Table Inheritance - Using joined subclasses" as described here: http://www.castleproject.org/activerecord/documentation/trunk/usersguide/typehierarchy.html
The following code is partly copied from there.
[ActiveRecord("entity"), JoinedBase]
public class Entity : ActiveRecordBase
{
...
private int id;
[PrimaryKey]
private int Id
{
get { return id; }
set { id = value; }
}
}
[ActiveRecord("entitycompany")]
public class CompanyEntity : Entity
{
private int com开发者_如何转开发p_id;
[JoinedKey("comp_id")]
public int CompId
{
get { return comp_id; }
set { comp_id = value; }
}
....
}
Now when I have a CompanyEntity loaded and access the ComId property it is always 0, but the inherited Id Property contains the correct value.
Edit:
I Probably should add that our Entities are automatically generate and I do not want to touch the generator.
Edit2:
Ok, I realize that I have to touch the generator in order to make it work. But still why isn't Active Record setting the Comp_id?
Question:
How can I tell ActiveRecord to also set the value of the JoinedKey in the child class so that CompId == Id?
I think you need to use:
[JoinedKey("comp_id")]
public override int Id { get { return base.Id; } }
... and the example they give is wrong.
This is quite an old question, but I ran into the same problem. The example on the Castle.ActiveRecord page is wrong.
You can solve the problem like this (your code example with commented modifications):
[ActiveRecord("entity"), JoinedBase]
public class Entity : ActiveRecordBase
{
...
protected int id; // use protected instead of private
[PrimaryKey]
private int Id
{
get { return id; }
set { id = value; }
}
}
[ActiveRecord("entitycompany")]
public class CompanyEntity : Entity
{
// private int comp_id; // this member variable is not required
[JoinedKey("comp_id")]
public int CompId
{
get { return id; } // access the member variable of the base class
set { id = value; } // access the member variable of the base class
}
....
}
I've just successfully tested it with my type hierarchy.
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