How to create a Multimap<K,V> from a Map<K, Collection<V>>?
I didn't find such a multimap construction... When I want to do this, I iterate over the map, and populate t开发者_运维百科he multimap. Is there an other way?
final Map<String, Collection<String>> map = ImmutableMap.<String, Collection<String>>of(
"1", Arrays.asList("a", "b", "c", "c"));
System.out.println(Multimaps.forMap(map));
final Multimap<String, String> expected = ArrayListMultimap.create();
for (Map.Entry<String, Collection<String>> entry : map.entrySet()) {
expected.putAll(entry.getKey(), entry.getValue());
}
System.out.println(expected);
The first result is {1=[[a, b, c, c]]}
but I expect {1=[a, b, c, c]}
Assuming you have
Map<String, Collection<String>> map = ...;
Multimap<String, String> multimap = ArrayListMultimap.create();
Then I believe this is the best you can do
for (String key : map.keySet()) {
multimap.putAll(key, map.get(key));
}
or the more optimal, but harder to read
for (Entry<String, Collection<String>> entry : map.entrySet()) {
multimap.putAll(entry.getKey(), entry.getValue());
}
This question is a little old, but I thought I'd give an updated answer. With Java 8 you could do something along the lines of
ListMultimap<String, String> multimap = ArrayListMultimap.create();
Map<String, Collection<String>> map = ImmutableMap.of(
"1", Arrays.asList("a", "b", "c", "c"));
map.forEach(multimap::putAll);
System.out.println(multimap);
This should give you {1=[a, b, c, c]}
, as desired.
Here is a useful generic version that I wrote for my StuffGuavaIsMissing class.
/**
* Creates a Guava multimap using the input map.
*/
public static <K, V> Multimap<K, V> createMultiMap(Map<K, ? extends Iterable<V>> input) {
Multimap<K, V> multimap = ArrayListMultimap.create();
for (Map.Entry<K, ? extends Iterable<V>> entry : input.entrySet()) {
multimap.putAll(entry.getKey(), entry.getValue());
}
return multimap;
}
And an immutable version:
/**
* Creates an Immutable Guava multimap using the input map.
*/
public static <K, V> ImmutableMultimap<K, V> createImmutableMultiMap(Map<K, ? extends Iterable<V>> input) {
ImmutableMultimap.Builder<K, V> builder = ImmutableMultimap.builder();
for (Map.Entry<K, ? extends Iterable<V>> entry : input.entrySet()) {
builder.putAll(entry.getKey(), entry.getValue());
}
return builder.build();
}
UPDATE: For what you're asking, I think you're going to need to fall back to Multimap.putAll
.
You can use the com.google.common.collect.Multimaps.flatteningToMultimap
as your stream collector.
Given map:
Map<Integer, Collection<String>> map = Map.of(
1, List.of("a", "b", "c"),
2, List.of("d", "e", "f"));
You can do the following:
Multimap<Integer, String> multimap = map.entrySet().stream()
.collect(flatteningToMultimap(Map.Entry::getKey, it -> it.getValue().stream(), HashMultimap::create));
Following code without Google's Guava library. It is used for double value as key and sorted order
Map<Double,List<Object>> multiMap = new TreeMap<Double,List<Object>>();
for( int i= 0;i<15;i++)
{
List<Object> myClassList = multiMap.get((double)i);
if(myClassList == null)
{
myClassList = new ArrayList<Object>();
multiMap.put((double) i,myClassList);
}
myClassList.add("Value "+ i);
}
List<Object> myClassList = multiMap.get((double)0);
if(myClassList == null)
{
myClassList = new ArrayList<Object>();
multiMap.put( (double) 0,myClassList);
}
myClassList.add("Value Duplicate");
for (Map.Entry entry : multiMap.entrySet())
{
System.out.println("Key = " + entry.getKey() + ", Value = " +entry.getValue());
}
LinkedListMultimap<String, String> mm = map.entrySet()
.stream()
.collect(
() -> LinkedListMultimap.create(map.size()),
(m, e) -> m.putAll(e.getKey(), e.getValue()),
(m1, m2) -> m1.putAll(m2));
There is another method one can use:
Multimaps#newMultimap
If you are using a collection extending List
or Set
, the docs recommend using the special methods Multimaps#newListMultimap
and Multimaps#newSetMultimap
.
import com.google.common.collect.Multimaps;
Multimaps.newListMultimap(myMap, ArrayList::new);
Multimaps.newSetMultimap(myMap, HashSet::new);
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