In jQuery, can you fadeOut() without losing the element's real estate? (invisible vs display: none)
Because I need to fadeIn() another element of the same size back in, is there a way to fadeOut() the element so that the space is kept, so that the other elements a开发者_运维问答re not re-flowed for a split second and then the fadeIn() will bring back another element with the same size?
Two techniques come to mind:
- Wrap the element in a div which occupies the correct amount of space.
- Use the .animate method to change the opacity of the item from 100% to 0%, then, when the animation completes, swap the new element in and once again use animate to change the opacity from 0% to 100%.
my suggestion is you wrap it with div... and put the same dimension on that div...
Keep the element you want to fade inside a fixed <div style="display:block;width:300px;height:200px;">
, then if you hide the element inside it, it will not affect the layout at all.
I have made my own fix. Before I run the fadeOut, I run this function:
/**
* Keep the window height, to avoid user being thrown up (i.e. on fade out, remove, hide, etc)
*/
function keepHeight() {
$('body').css('min-height', $(document).height());
}
So for instance:
/**
* Keep window height
*/
keepHeight();
/**
* Fade out
*/
$('#someDiv').fadeOut();
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