SELECT statement for a VIEW in MySQL not returning all the wanted rows
I need help with my MySQL query:
CREATE OR REPLACE
DEFINER = CURRENT_USER
VIEW users_phpscheduleit
AS
SELECT
u.uid AS memberid,
pass AS password,
mail AS email,
pv1.value AS fname,
pv2.value AS lname,
pv3.value AS phone,
e_add, e_mod, e_del, e_html, e_app,
is_admin, lang, timezone_scheduleit,
institution, logon_name
FROM
users u, profile_values pv1, profile_values pv2, profile_values pv3
WHERE
u.uid = pv1.uid AND u.uid = pv2.uid AND u.uid = pv3.uid
AND
pv1.fid = 26
AND
pv2.fid = 27
AND
pv3.fid = 8;
This cannot contain a list of things, in order for it to remain editable using the view table in an INSER开发者_开发技巧T or UPDATE query in a PHP application I am integrating with another PHP system. My users table is 442 long and I'm only getting 1/2 of them.
Problem:
I am not able to get all the rows in theusers
table because they obviously don't all have a profile_values.fid
of 26, 27 or 8.
Q: How can I tweak the statement to still include those but without breaking the rules that enable editability?
ps.for the curious I'm trying to authenticate phpScheduleIt users through the Drupal DB
I am not able to get all the rows in the users table because they obviously don't all have a profile_values.fid of 26, 27 or 8.
That's because your query uses INNER JOINs, when you need to use an OUTER (IE LEFT/RIGHT) JOIN if you want data where there's a possibility of no supporting record. Your query is in ANSI-89 syntax, which doesn't consistently implement OUTER JOIN syntax. Here's your query rewritten using ANSI-92 syntax:
SELECT u.uid AS memberid,
pass AS password,
mail AS email,
pv1.value AS fname,
pv2.value AS lname,
pv3.value AS phone,
e_add, e_mod, e_del, e_html, e_app,
is_admin, lang, timezone_scheduleit,
institution, logon_name
FROM USERS u
LEFT JOIN PROFILE_VALUES pv1 ON pv1.uid = u.uid
AND pv1.fid = 26
LEFT JOIN PROFILE_VALUES pv2 ON pv2.uid = u.uid
AND pv2.fid = 27
LEFT JOIN PROFILE_VALUES pv3 ON pv3.uid = u.uid
AND pv3.fid = 8
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