Adding a class instance as value to a dictionary
I've an xml file "Sample.xml"
<RootElement>
<Children>
<Child Name="FirstChild" Start="0" End="2">
<Sibling Name="Test1" />
<Sibling Name="Test2" />
<AdditionalSibling Name="Add_Test_1" />
<AdditionalSibling Name="Add_Test_2" />
<MissingSibling Name="Miss_Test_1" />
<MissingSibling Name="Miss_Test_2" /
</Child>
<Child Name="SecondChild" Start="0" End="2">
<Sibling Name="Test3" />
<Sibling Name="Test4" />
</Child>
<Child Name="ThirdChild" Start="0" End="2">
<Sibling Name="Test5" />
<Sibling Name="Test6" />
</Child>
<Child Name="FourthChild" Start="0" End="2">
<Sibling Name="Test7" />
<Sibling Name="Test8" />
</Child>
<Child Name="FifthChild" Start="0" End="2">
<Sibling Name="Test9" />
<Sibling Name="Test10" />
</Child>
<Child Name="SixthChild" Start="0" End="2">
<Sibling Name="Test11" />
<Sibling Name="Test12" />
</Child>
<MatchedChilds>
<Child Name="FirstChild" />
<Child Name="SecondChild" />
<Child Name="ThirdChild" />
<Child Name="FourthChild" />
<Child Name="FifthChild" />
<Child Name="SixthChild" />
</MatchedChilds>
</Children>
</RootElement>
And a Class "SampleClass"
public class SampleClass
{
string Start;
string End;
List<string> Siblings;
List<string> AdditionalSiblings;
List<string> MissingSiblings;
public SampleClass()
{
Start= "";
End = "";
Siblings = new List<string>();
AdditionalSiblings = new List<string>();
MissingSiblings = new List<string>();
}
public SampleClass( string St, string En,List<string> S, List<string> AS, List<string> MS)
{
Start= St;
End = En;
Siblings = S;
AdditionalSiblings = AS;
MissingSiblings = MS;
}
}
and in another class i've declared a Dictonary Like
Dictionary<string, SampleClass> m_dictSample = new Dictionary<string, SampleClass>();
i need to fill this dictonary with the contents of the file ..
I'm using Xml Linq for this..
XDocument l_XDOC = XDocument.Load(Application.StartupPath + "\\Sample.xml");
m_dictSample = (from element in l_XDOC.Descendants("Child")
group element by element.Attribute("Name").Value into KeyGroup
select KeyGroup )
.ToDictionary(grp => grp.Key,
grp => new
SampleClass(grp.Attributes(开发者_如何学C"Start").ToList()[0].Value.ToString(),
grp.Attributes("End").ToList()[0].Value.ToString(),
grp.Descendants("Sibling").Attributes("Name").Select(l_Temp => l_Temp.Value).ToList(),
grp.Descendants("AdditionalSibling").Attributes("Name").Select(l_Temp => l_Temp.Value).ToList(),
grp.Descendants("MissingSibling").Attributes("Name").Select(l_Temp => l_Temp.Value).ToList()));
This query is working properly for the above described file.
But if the file have more than one Element with same name, or an element with no "start" and "end" attribute make an exception while executing the query.
I've problem with the following lines
grp.Attributes("Start").ToList()[0].Value.ToString(),
grp.Attributes("End").ToList()[0].Value.ToString()
please give me a better way to do this
And i need to fill a listView with the contents of the Dictonary like
S.no Child Siblings Additional Siblings Missing Siblings
1 FirstChild Test1,Test2 Add_Test_1,Add_Test_2 Miss_Test_1,Miss_Test_2
2 SecondChild Test3,Test4
3 ThirdChild Test5,Test6
now i'm using for loop for this
please give me a better way to do this..
You can't use a Dictionary you have to use a Lookup collection
Dictionaries require that each key has a 1-1 mapping to a unique value.
What you're looking for is a Lookup collection.
See this for more info.
Given the way that you have written your query I don't see why you'd be getting an exception if you had two Child
elements with the same name. If anything their data would just get combined into a single key instance in your dictionary. To fix the exception you receive when a Start
attribute doesn't exist just do a conditional operator test ? :
to see if results were returned from your attribute query. That said the below code should work for you with the disclaimer that just because this works doesn't mean it's best practice. In many ways I am a LINQ neophyte myself.
Dictionary<string, SampleClass> dict =
(from element in xDoc.Descendants("Child")
group element by element.Attribute("Name").Value
into kGrp
select kGrp)
.ToDictionary(grp => grp.Key,
grp => new SampleClass
{
Start = grp.Attributes("Start").Count() > 0
? grp.Attributes("Start")
.ToList()[0].Value.ToString()
: String.Empty
,End = grp.Attributes("End").Count() > 0
? grp.Attributes("End")
.ToList()[0].Value.ToString()
: String.Empty
,Siblings =
grp.Descendants("Sibling")
.Attributes("Name")
.Select(l_Temp => l_Temp.Value).ToList()
,AdditionalSiblings =
grp.Descendants("AdditionalSibling")
.Attributes("Name")
.Select(l_Temp => l_Temp.Value).ToList()
,MissingSiblings =
grp.Descendants("MissingSibling")
.Attributes("Name")
.Select(l_Temp => l_Temp.Value).ToList()
});
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