How to code a batch file to copy and rename the most recently dated file?

I'm trying to code a batch file to copy only the most recently dated file in a given folder to another directory on the local machine, and simultaneously rename it as it does.

I've found a very similar question here

How do I write a Windows batch script to copy the newest file from a directory?

and have managed to cobble together the below code from other forums too, but have hit a brick wall as it only results in the batch file itself being copied to the destination folder. It doesn't matter to me where the batch file itself sits in order f开发者_开发知识库or this to run.

The source folder is C:! BATCH and the destination folder is C:\DROP

The code is below, apologies if this is a glaringly obvious answer but it's literally the first foray into coding batch files for me... Thanks!

@echo off

setLocal EnableDelayedExpansion

pushd C:\! BATCH

for /f "tokens=* delims= " %%G in ('dir/b/od') do (set newest=%%G)

copy "!newest!" C:\DROP\

PAUSE

Try moving the pushd command above the setLocal command.

My guess is that the "!" character has a special meaning for delayed expansion, so you may not be able to use it as part of a path name after you turn on delayed expansion.

You could also remove the exclamation point from your path if you don't really need it, that might be easier.

I think this small mods enable your script to do what you want

 @echo on
 setLocal DisableDelayedExpansion
 pushd "C:\! BATCH"
 setLocal EnableDelayedExpansion

 for /f "tokens=* delims= " %%G in ('dir/b/od') do (set newest=%%G)

 copy %newest% C:\DROP\newname.txt

 PAUSE
 POPD

newname.txt ... is the new name :)