Reading a single char in Java

How can a char be 开发者_JS百科entered in Java from keyboard?

You can either scan an entire line:

Scanner s = new Scanner(System.in);
String str = s.nextLine();

Or you can read a single char, given you know what encoding you're dealing with:

char c = (char) System.in.read();

You can use Scanner like so:

Scanner s= new Scanner(System.in);
char x = s.next().charAt(0);

By using the charAt function you are able to get the value of the first char without using external casting.

Using nextline and System.in.read as often proposed requires the user to hit enter after typing a character. However, people searching for an answer to this question, may also be interested in directly respond to a key press in a console!

I found a solution to do so using jline3, wherein we first change the terminal into rawmode to directly respond to keys, and then wait for the next entered character:

var terminal = TerminalBuilder.terminal()
terminal.enterRawMode()
var reader = terminal.reader()

var c = reader.read()

<dependency>
    <groupId>org.jline</groupId>
    <artifactId>jline</artifactId>
    <version>3.12.3</version>
</dependency>

You can use a Scanner for this. It's not clear what your exact requirements are, but here's an example that should be illustrative:

    Scanner sc = new Scanner(System.in).useDelimiter("\\s*");
    while (!sc.hasNext("z")) {
        char ch = sc.next().charAt(0);
        System.out.print("[" + ch + "] ");
    }

If you give this input:

123 a b c x   y   z

The output is:

[1] [2] [3] [a] [b] [c] [x] [y] 

So what happens here is that the Scanner uses \s* as delimiter, which is the regex for "zero or more whitespace characters". This skips spaces etc in the input, so you only get non-whitespace characters, one at a time.

i found this way worked nice:

    {
    char [] a;
    String temp;
    Scanner keyboard = new Scanner(System.in);
    System.out.println("please give the first integer :");
    temp=keyboard.next();
    a=temp.toCharArray();
    }

you can also get individual one with String.charAt()

Here is a class 'getJ' with a static function 'chr()'. This function reads one char.

import java.io.InputStreamReader;
import java.io.BufferedReader;
import java.io.IOException;

class getJ {
    static char  chr()throws IOException{  
        BufferedReader bufferReader =new BufferedReader(new InputStreamReader(System.in));
        return bufferReader.readLine().charAt(0);
    }
}

In order to read a char use this:

anyFunc()throws IOException{
...
...
char c=getJ.chr();
}

Because of 'chr()' is static, you don't have to create 'getJ' by 'new' ; I mean you don't need to do:

getJ ob = new getJ;
c=ob.chr();

You should remember to add 'throws IOException' to the function's head. If it's impossible, use try / catch as follows:

anyFunc(){// if it's impossible to add 'throws IOException' here
...
try
{
char c=getJ.chr(); //reads a char into c
} 
catch(IOException e)
{
System.out.println("IOException has been caught");
}

Credit to: tutorialspoint.com

See also: geeksforgeeks.

java bufferedreader input getchar char

.... char ch; ... ch=scan.next().charAt(0); . . It's the easy way to get character.

Maybe you could try this code:

import java.io.*;
public class Test
{
public static void main(String[] args)
{
try
  {
  BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
  String userInput = in.readLine();
  System.out.println("\n\nUser entered -> " + userInput);
  }
  catch(IOException e)
  {
  System.out.println("IOException has been caught");
  }
 }
}