Using LIKE in MySQL SELECT fields

I've been trying to select the status of doing a LIKE comparison:

SELECT (`my_column` LIKE '%thepattern'%) AS `did_match`

Thanks!

Edit: Just to clarify this was used so I could get this:

SELECT
     (CASE WHEN `title` LIKE '%keyword%' THEN 20 ELSE 0 END) +
     (CASE WHEN `desc` LIKE '开发者_运维问答%keyword%' THEN 10 ELSE 0 END)
     AS `match`
FROM myTable
ORDER BY `match`

You need to use:

SELECT t.my_column AS did_match
  FROM YOUR_TABLE t
 WHERE t.my_column LIKE '%thepattern%'

Replace YOUR_TABLE with the name of your table...

Without a FROM clause, MySQL (and SQL Server) will allow the query, but not against any data.

Not sure I understand the question, and it looks like OMG Ponies has figured it out better than I have, but in case this helps:

SELECT CASE WHEN `my_column` LIKE '%thepattern%' 
       THEN 'did_match' ELSE 'no_match' END CASE AS MYTEST
  FROM ...

Link to CASE statement documentation.