nul terminating a int array

gcc 4.4.4 c89

I was just experimenting with a int array. And something just came to my mind. Can I nul terminate it. For example, I am using a 0 to nul terminate. However, 0 could well be a valid value in this array.

The code below will terminate after the 5. Even though I mean 0 to be a valid number. However, I could specify the size of the array. But in this case, I don't want to this as I am jus开发者_C百科t interested in this particular problem.

Many thanks for any advice,

#include <stdio.h>

static void test(int *p);

int main(void)
{
    int arr[] = {30, 450, 14, 5, 0, 10, '\0'};

    test(arr);

    return 0;
}

static void test(int *p)
{
    while(*p) {
        printf("Array values [ %d ]\n", *p++);
    }
}

In short, no. Technically nul characters are equally valid in strings too, it's just a convention that we use them for marking the end of a string, and all the standard library functions expect that. There are "double nul-terminated" strings that end in \0\0 for cases where a string needs to contain a \0, but then of course you have the problem of not being able to store \0\0 in the string.

If you don't want to store an array's size separately (or use trickery like sizeof), you need to come up with a sentinel that can be stored in that type but you know won't be part of the array; you could use 45 as long as you're sure arr won't have that as a valid value, it just needs to be unique

In order to use a sentinel value, obviously you have to find a value that is not otherwise valid data. That is one of the drawbacks of using a sentinel (the other being the linear search required to find the length). How does something like 0xFFFF work for you?

If this were C++, I'd suggest making a class with an associated length member (or better yet, just using std::vector). For C you should probably just keep the separate length variable yourself. You can get fancy and put it and the array together in a struct if you like.

Simply put, \0 is the same as 0, so if you have a zero in your array your code will mistake that for the array's end:

int arr[] = {30, 450, 14, 5, 0, 10, '\0'};
                             ^ this is the end of the array

Edit: note that by "end of the array" I mean the conceptual end of the array as defined by your algorithm, rather than the actual extents of the data laid out in memory by the C programming language.

Well, you can also change your sentinel from \0 to \\0. And, accordingly, a slight modification in the condition for while loop will get you around your problem.

while(*p != '\\0')

Now, 0 will not be treated as terminator for the integer array and the whole array gets printed.