Groovy pretty print XmlSlurper output from HTML?
I am using several different versions to do this but all seem to result in this error:
[Fatal Error] :1:171: The prefix "xmlns" cannot be bound to any namespace explicitly; neither can the namespace for "xmlns" be bound to any prefix explicitly.
I load html as:
// Load html file
def fis=new FileInputStream("2.html")
def html=new XmlSlurper(new org.cyberneko.html.parsers.SAXParser()).parseText(fis.text)
Versions I've tried:
http://johnrellis.blogspot.com/2009/08/hmmm_04.html
import groovy.xml.StreamingMarkupBuilder
import groovy.xml.XmlUti开发者_如何学编程l
def streamingMarkupBuilder=new StreamingMarkupBuilder()
println XmlUtil.serialize(streamingMarkupBuilder.bind{mkp.yield html})
http://old.nabble.com/How-to-print-XmlSlurper%27s-NodeChild-with-indentation--td16857110.html
// Output
import groovy.xml.MarkupBuilder
import groovy.xml.StreamingMarkupBuilder
import groovy.util.XmlNodePrinter
import groovy.util.slurpersupport.NodeChild
def printNode(NodeChild node) {
def writer = new StringWriter()
writer << new StreamingMarkupBuilder().bind {
mkp.declareNamespace('':node[0].namespaceURI())
mkp.yield node
}
new XmlNodePrinter().print(new XmlParser().parseText(writer.toString()))
}
Any advice?
Thank you! Misha
The problem is namespaces. Here is the solution:
def saxParser=new org.cyberneko.html.parsers.SAXParser()
saxParser.setFeature('http://xml.org/sax/features/namespaces',false)
new XmlSlurper(saxParser).parseText(text)
import groovy.xml.XmlUtil
println XmlUtil.serialize(new StreamingMarkupBuilder().bind {
mkp.yield page
})
Thank you! Misha
Still don't have an answer but if I use XmlParser then
def html=new XmlSlurper(new org.cyberneko.html.parsers.SAXParser()).parseText(somehtml)
new XmlNodePrinter(preserveWhitespace:true).print(html)
Will pretty print.
Also if you get a StreamingMarkupBuilder, you can do:
import groovy.xml.XmlUtil
println XmlUtil.serialize(new StreamingMarkupBuilder().bind {
... make your markup here ...
}
)
Misha
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