Prolog Beginner: Trivial Example that I cannot get to work.

I have some prolog. The lessThanTen and example predicates work as expected however the exam predicate does not work.

lessThanTen(9).
lessThanTen(8).
lessThanTen(7).
lessThanTen(6).
lessThanTen(5).
lessThanTen(4).
lessThanTen(3).
lessThanTen(2).
lessThanTen(1).
lessThanTen(0).

% This should always return 5.
example(X) :-
        X is 5.

% This should return all values that ar开发者_高级运维e less than ten.
exam(X) :-
        X is lessThanTen(Y).

Here is the output:

% swipl
...

?- [addv1]. 
Warning: /.../addv1.pl:17:
        Singleton variables: [Y]
% addv1 compiled 0.00 sec, 1,484 bytes
true.

?- lessThanTen(X).
X = 9 ;
X = 8 ;
X = 7 ;
...

?- example(X).
X = 5.

?- exam(X).
ERROR: is/2: Arithmetic: `lessThanTen/1' is not a function
?- exam(5).
ERROR: is/2: Arithmetic: `lessThanTen/1' is not a function

I am thinking that the warning I am getting is pretty key.

The is operator expects its right-hand argument - your lessThanTen(Y) - to be an arithmetic expression. It, of course, isn't.

Also, exam/1 just looks wrong: what's Y? The clause takes a single argument X.

lessThanTen(9).
lessThanTen(8).
lessThanTen(7).
lessThanTen(6).
lessThanTen(5).
lessThanTen(4).
lessThanTen(3).
lessThanTen(2).
lessThanTen(1).
lessThanTen(0).


example(X) :-
        X is 5.


exam(X) :-
        lessThanTen(X).