How do I create a ZIP file in Java?
What is the Java equivalent to this jar command:
C:\>jar cvf myjar.jar directory
I'd like to create this jar file programmatically as I can't be assured that the jar
command will be on the system path where I could just run the external process.
Edit: All I want is to archive (and compress) a directory开发者_Python百科. Doesn't have to follow any java standard. Ie: a standard zip is fine.
// These are the files to include in the ZIP file
String[] source = new String[]{"source1", "source2"};
// Create a buffer for reading the files
byte[] buf = new byte[1024];
try {
// Create the ZIP file
String target = "target.zip";
ZipOutputStream out = new ZipOutputStream(new FileOutputStream(target));
// Compress the files
for (int i=0; i<source.length; i++) {
FileInputStream in = new FileInputStream(source[i]);
// Add ZIP entry to output stream.
out.putNextEntry(new ZipEntry(source[i]));
// Transfer bytes from the file to the ZIP file
int len;
while ((len = in.read(buf)) > 0) {
out.write(buf, 0, len);
}
// Complete the entry
out.closeEntry();
in.close();
}
// Complete the ZIP file
out.close();
} catch (IOException e) {
}
You can also use the answer from this post How to use JarOutputStream to create a JAR file?
Everything you'll want is in the java.util.jar package:
http://java.sun.com/javase/6/docs/api/java/util/jar/package-summary.html
精彩评论