C equivalent of C++ delete[] (char *)

What is the C equivalent of C++

delete[] (char *) foo->bar;

Edit: I'm converting some C++ code to ANSI C. And it had:

typedef struct keyvalue
{
  char *key;
  void *value;
  struct keyvalue *next;
} keyvalue_rec;

// ...

  for (
 开发者_高级运维   ptr = this->_properties->next, last = this->_properties;
    ptr!=NULL;
    last = ptr, ptr = ptr->next)
  {
    delete[] last->key;
    delete[] (char *) last->value;
    delete last;
  }

Would this do it for C?

free(last->key);
free(last->value);
free(last)

In C, you don't have new; you just have malloc(); to free memory obtained by a call to malloc(), free() is called.

That said, why would you cast a pointer to (char*) before passing it to delete? That's almost certainly wrong: the pointer passed to delete must be of the same type as created with new (or, if it has class type, then of a base class with a virtual destructor).

Just plain 'ol free(). C makes no distinction between arrays and individual variables.

Same as for non-arrays.

free(foo->bar)

The equivalent would be:

free(foo->bar);

since you were typecasting it to (char *) which means whatever the actual type of 'bar' was there would have been no destructor called as a result of the cast.

The C equivalent to delete and delete[] is just free ?