开发者

printing uid of a file on linux system

i am learning c programming. I am trying to make my own program similar to ls command but with less options.what i am doing is taking input directory/file name as argument and then gets all directory entry with dirent struct(if it is directory) .

After it i use stat() to take all information of the file but here is my problem when i use write() to print these value its fine but when i want to print these with printf() i get warninng : format ‘%ld’ expects type ‘long int’, but argument 2 has type ‘__uid_t’. I don't know what should use at place of %ld开发者_运维百科 and also for other special data types.


There is no format specifier for __uid_t, because this type is system-specific and is not the part of C standard, and hence printf is not aware of it.

The usual workaround is to promote it to a type that would fit the entire range of UID values on all the systems you are targeting:

printf("%lu\n", (unsigned long int)uid); /* some systems support 32-bit UIDs */


You could cast it to a long int:

printf("foobar: %ld\n", (long int)your_uid_t_variable);
0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜