simple way for QuerySet union and subtraction in django?
Consider two QuerySet objects of the same class. Is there a simple way to unify them into a single QuerySet by calculating 开发者_如何学Gothe union? Also, is there a simple way to subtract them? Removing all elements that appear in both sets from one of the sets?
Since Django 1.11, QuerySets have union()
, intersection()
and difference()
methods.
It's also possible to use &
and |
infix operators with QuerySets (I could not find a reference to this in the docs, so I guess union()
and intersection()
is the preferred way to combine two querysets.
qs3 = qs1.union(qs2) # or qs3 = qs1 | qs2
qs3 = qs1.intersection(qs2) # or qs3 = qs1 & qs2
qs3 = qs1.difference(qs2) # no operator for this
You can also use Q()
objects which like QuerySets implement |
and &
, and additionally the invert prefix operator ~
.
Neither class implement the xor / symmetric difference infix operator ^
.
Subtract a QuerySet from another QuerySet using the same model.
This works - but is probably slowly
queryset_with_hello = Blog.objects.filter(name__icontains='hello')
queryset_without_hello = Blog.objects.exclude(pk__in=queryset_with_hello)
Read the performance considerations in django documentation:
https://docs.djangoproject.com/en/dev/ref/models/querysets/#in
Going back to django's documentation, you can:
new_query_set = query_set_1 | query_set_2
This works as a logical OR which is actually addition without duplicates. This answers the addition aspect and AFAIK does not hit the db at all!
new_query_set = query_set_1 & query_set_2
This works as a logical AND.
Still missing how to subtract QuerySets. It's hard for me to believe this has not been dealt with elegantly by the community...
You can use the Q
object.
The syntax could be something like this:
added_query_set = YourModel.objects.\
filter(Q(id__in=old_query_set_1)|Q(id__in=old_query_set_2))
You probably can optimize based on your actual needs and get the amount of db hits down (right now it's 3), but this should get you started.
I think for operations as this you need to evalute them. So you can call list()
on them and work on them with the common python list operations!
qs3 = qs1.union(qs2) # union
qs4 = qs1.difference(qs2) # subtraction
精彩评论