JSON serialization of Google App Engine models
I've been searching for quite a while with no success. My project isn't using Django, is there a simple way to serialize App Engine models (google.appengine.ext.db.Model) into JSON or do 开发者_StackOverflowI need to write my own serializer?
Model:
class Photo(db.Model):
filename = db.StringProperty()
title = db.StringProperty()
description = db.StringProperty(multiline=True)
date_taken = db.DateTimeProperty()
date_uploaded = db.DateTimeProperty(auto_now_add=True)
album = db.ReferenceProperty(Album, collection_name='photo')
A simple recursive function can be used to convert an entity (and any referents) to a nested dictionary that can be passed to simplejson
:
import datetime
import time
SIMPLE_TYPES = (int, long, float, bool, dict, basestring, list)
def to_dict(model):
output = {}
for key, prop in model.properties().iteritems():
value = getattr(model, key)
if value is None or isinstance(value, SIMPLE_TYPES):
output[key] = value
elif isinstance(value, datetime.date):
# Convert date/datetime to MILLISECONDS-since-epoch (JS "new Date()").
ms = time.mktime(value.utctimetuple()) * 1000
ms += getattr(value, 'microseconds', 0) / 1000
output[key] = int(ms)
elif isinstance(value, db.GeoPt):
output[key] = {'lat': value.lat, 'lon': value.lon}
elif isinstance(value, db.Model):
output[key] = to_dict(value)
else:
raise ValueError('cannot encode ' + repr(prop))
return output
This is the simplest solution I found. It requires only 3 lines of codes.
Simply add a method to your model to return a dictionary:
class DictModel(db.Model):
def to_dict(self):
return dict([(p, unicode(getattr(self, p))) for p in self.properties()])
SimpleJSON now works properly:
class Photo(DictModel):
filename = db.StringProperty()
title = db.StringProperty()
description = db.StringProperty(multiline=True)
date_taken = db.DateTimeProperty()
date_uploaded = db.DateTimeProperty(auto_now_add=True)
album = db.ReferenceProperty(Album, collection_name='photo')
from django.utils import simplejson
from google.appengine.ext import webapp
class PhotoHandler(webapp.RequestHandler):
def get(self):
photos = Photo.all()
self.response.out.write(simplejson.dumps([p.to_dict() for p in photos]))
In the latest (1.5.2) release of the App Engine SDK, a to_dict()
function that converts model instances to dictionaries was introduced in db.py
. See the release notes.
There is no reference to this function in the documentation as of yet, but I have tried it myself and it works as expected.
To serialize models, add a custom json encoder as in the following python:
import datetime
from google.appengine.api import users
from google.appengine.ext import db
from django.utils import simplejson
class jsonEncoder(simplejson.JSONEncoder):
def default(self, obj):
if isinstance(obj, datetime.datetime):
return obj.isoformat()
elif isinstance(obj, db.Model):
return dict((p, getattr(obj, p))
for p in obj.properties())
elif isinstance(obj, users.User):
return obj.email()
else:
return simplejson.JSONEncoder.default(self, obj)
# use the encoder as:
simplejson.dumps(model, cls=jsonEncoder)
This will encode:
- a date as as isoformat string (per this suggestion),
- a model as a dict of its properties,
- a user as his email.
To decode the date you can use this javascript:
function decodeJsonDate(s){
return new Date( s.slice(0,19).replace('T',' ') + ' GMT' );
} // Note that this function truncates milliseconds.
Note: Thanks to user pydave who edited this code to make it more readable. I had originally had used python's if/else expressions to express jsonEncoder
in fewer lines as follows: (I've added some comments and used google.appengine.ext.db.to_dict
, to make it clearer than the original.)
class jsonEncoder(simplejson.JSONEncoder):
def default(self, obj):
isa=lambda x: isinstance(obj, x) # isa(<type>)==True if obj is of type <type>
return obj.isoformat() if isa(datetime.datetime) else \
db.to_dict(obj) if isa(db.Model) else \
obj.email() if isa(users.User) else \
simplejson.JSONEncoder.default(self, obj)
You don't need to write your own "parser" (a parser would presumably turn JSON into a Python object), but you can still serialize your Python object yourself.
Using simplejson:
import simplejson as json
serialized = json.dumps({
'filename': self.filename,
'title': self.title,
'date_taken': date_taken.isoformat(),
# etc.
})
For simple cases, I like the approach advocated here at the end of the article:
# after obtaining a list of entities in some way, e.g.:
user = users.get_current_user().email().lower();
col = models.Entity.gql('WHERE user=:1',user).fetch(300, 0)
# ...you can make a json serialization of name/key pairs as follows:
json = simplejson.dumps(col, default=lambda o: {o.name :str(o.key())})
The article also contains, at the other end of the spectrum, a complex serializer class that enriches django's (and does require _meta
-- not sure why you're getting errors about _meta missing, perhaps the bug described here) with the ability to serialize computed properties / methods. Most of the time you serialization needs lay somewhere in between, and for those an introspective approach such as @David Wilson's may be preferable.
Even if you are not using django as a framework, those libraries are still available for you to use.
from django.core import serializers
data = serializers.serialize("xml", Photo.objects.all())
If you use app-engine-patch it will automatically declare the _meta
attribute for you, and then you can use django.core.serializers
as you would normally do on django models (as in sledge's code).
App-engine-patch has some other cool features such has an hybrid authentication (django + google accounts), and the admin part of django works.
Mtgred's answer above worked wonderfully for me -- I slightly modified it so I could also get the key for the entry. Not as few lines of code, but it gives me the unique key:
class DictModel(db.Model):
def to_dict(self):
tempdict1 = dict([(p, unicode(getattr(self, p))) for p in self.properties()])
tempdict2 = {'key':unicode(self.key())}
tempdict1.update(tempdict2)
return tempdict1
I've extended the JSON Encoder class written by dpatru to support:
- Query results properties (e.g. car.owner_set)
- ReferenceProperty - recursively turn it into JSON
Filtering properties - only properties with a
verbose_name
will be encoded into JSONclass DBModelJSONEncoder(json.JSONEncoder): """Encodes a db.Model into JSON""" def default(self, obj): if (isinstance(obj, db.Query)): # It's a reference query (holding several model instances) return [self.default(item) for item in obj] elif (isinstance(obj, db.Model)): # Only properties with a verbose name will be displayed in the JSON output properties = obj.properties() filtered_properties = filter(lambda p: properties[p].verbose_name != None, properties) # Turn each property of the DB model into a JSON-serializeable entity json_dict = dict([( p, getattr(obj, p) if (not isinstance(getattr(obj, p), db.Model)) else self.default(getattr(obj, p)) # A referenced model property ) for p in filtered_properties]) json_dict['id'] = obj.key().id() # Add the model instance's ID (optional - delete this if you do not use it) return json_dict else: # Use original JSON encoding return json.JSONEncoder.default(self, obj)
As mentioned by https://stackoverflow.com/users/806432/fredva, the to_dict works great. Here is my code i'm using.
foos = query.fetch(10)
prepJson = []
for f in foos:
prepJson.append(db.to_dict(f))
myJson = json.dumps(prepJson))
There's a method, "Model.properties()", defined for all Model classes. It returns the dict you seek.
from django.utils import simplejson
class Photo(db.Model):
# ...
my_photo = Photo(...)
simplejson.dumps(my_photo.properties())
See Model properties in the docs.
These APIs (google.appengine.ext.db) are no longer recommended. Apps that use these APIs can only run in the App Engine Python 2 runtime and will need to migrate to other APIs and services before migrating to the App Engine Python 3 runtime. To know more: click here
To serialize a Datastore Model instance you can't use json.dumps (haven't tested but Lorenzo pointed it out). Maybe in the future the following will work.
http://docs.python.org/2/library/json.html
import json
string = json.dumps(['foo', {'bar': ('baz', None, 1.0, 2)}])
object = json.loads(self.request.body)
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