C++ question: boost::bind receive other boost::bind
I want to make this code work properly, what should I do?
giving this error on the last line.
what am I doing wrong? i know boost::bind need a type but i'm not getting. help
class A
{
public:
template <class Handle>
void bindA(Handle h)
{
h(1, 2);
}
};
class B
{
public:
void bindB(int number, int number2)
{
std::cout << "1 " << number << "2 " << number2 << std::endl;
}
};
template < class Han > struct Wrap_
{
Wrap_(Han h) : h_(h) {}
template<typename Arg1, typename Arg2> void operator()(Arg1 arg1, Arg2 arg2)
{
h_(arg1, arg2);
}
Han h_;
};
template< class Handler >
inline Wrap_<Handler> make(Handler h)
{
return Wrap_<Handler> (h);
}
int main()
{
A a;
B b;
((boost::bind)(&B::bindB, b, _1, _2))(1, 2);
((boost::bind)(&A::bindA, a, make(boost::bind(&B::bindB, b, _1, _2))))();
/*i want compiled success an开发者_如何学编程d execute success this code*/
}
The problem that you are having is that you are trying to bind to a templated function. In this case you need to specify the template type of the method you are calling to bind.
This is happening for the method A::bindA
. See below for a code fragment for main that compiles correctly with the supplied classes.
Incidentally in the example I use boost::function (the sister library to bind) to specify what type of function pointers are being used. I think this makes it far more readable and would highly recommend that you become familiar with it if you are going to continue using bind.
#include "boost/bind.hpp"
#include "boost/function.hpp"
int main(int c, char** argv)
{
A a;
B b;
typedef boost::function<void(int, int)> BFunc;
typedef boost::function<void(BFunc)> AFunc;
BFunc bFunc( boost::bind(&B::bindB, b, _1, _2) );
AFunc aFunc( boost::bind(&A::bindA<BFunc>, a, make(bFunc)) );
bFunc(1,2);
}
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