开发者

Retrieve object from jquery in php script

I'm trying to rebuild an object encoded with Json but i'm not getting any value.

JQuery:

$.post("views/insert_tasks.php",{ clickedRows : clickrows , <?php echo "tasks:'" . json_encode($tasks) . "'"; ?> }, function(data)
{开发者_开发问答

});

this is the PHPcode to retrieve the object:

$tasks = json_decode(stripslashes($_POST['tasks']), true);

$tasks is empty after execute the code above.

This is what I'm getting with the $_POST['tasks']:

[{"task_id":"1","description":"<p>Fazer heroi</p>","createdat":"Saturday 22nd of May 2010 11:37:37 PM","createdby":"Miguel Cardoso","max_requests":"2","max_duration":"5","job_id":"Concept Artist"},{"task_id":"2","description":"<p>teste2</p>","createdat":"Sunday 23rd of May 2010 11:23:55 AM","createdby":"Miguel Cardoso","max_requests":"2","max_duration":"5","job_id":"3D Modeller"},{"task_id":"3","description":"<p>teste3</p>","createdat":"Sunday 23rd of May 2010 11:45:39 AM","createdby":"Miguel Cardoso","max_requests":"1","max_duration":"10","job_id":"Writer"}]

What I'm doing wrong?


Thanks for your reply Brian. I get it work replacing:

$tasks = json_decode(stripslashes($_POST['tasks']), true);

by

$tasks = json_decode($_POST['tasks']);

I was seeing the content of the variable $tasks writing it to a file. Here is the all code of php file:

<?php
session_start();

require_once("../database/db_connect.php");

if(isset($_POST['clickedRows'])) 
{ 
    $clickedRows = json_decode($_POST['clickedRows']);
    $tasks = json_decode($_POST['tasks']); 

    foreach($clickedRows as $i)
    {
        $task_id = $tasks[$i]->task_id;

        $myFile = "debug.txt";
        $fh = fopen($myFile, 'w') or die("can't open file");
        fwrite($fh, $_POST['tasks']);

        fclose($fh);

        $user_id = $_SESSION['id'];
        $requestedat = date('l jS \of F Y h:i:s A');
        $requestedby = $_SESSION['first'] . " " . $_SESSION['last'];


        $sql ="INSERT INTO 
        darkfuture.users_tasks
        (
          `task_id`,
          `user_id`,
          `requestedat`,
          `requestedby`
        ) 
        VALUE (
          $task_id,
          $user_id,
          '$requestedat',
          '$requestedby'
        )";

        $res = mysql_query($sql) or die(mysql_error());
   }
}
?>
0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜