Returning a row from a With clause
I'm开发者_如何学Go trying to make a Function that retruns a value.
In my function I have this script:
WITH t_new AS
(
SELECT PersIDOLD, PersIDNEW, RightsMUT,
SUM(gap) over(ORDER BY PersIDOLD, PersIDNEW) grp
FROM
(
SELECT h1.*,
CASE
WHEN h1.PersIDNEW = lag(h1.PersIDNEW)
over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
OR h1.PersIDOLD = lag(h1.PersIDOLD)
over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
THEN 0
ELSE 1
END gap
FROM HelpTable1 h1
)
)
SELECT PERSIDNEW, RIGHTSMUT
FROM t_new
WHERE grp =
(
SELECT grp FROM t_new WHERE PersIDNEW = 12 -- going to be a variable
)
the return is like this:
http://img59.imageshack.us/img59/6733/tablei.gif
Now I want to return row 3
coze it has a 1
in row RightsMUT
How could I do this?
I tried to do it with 2 With
but oracle does not support 2 with yet.
Let me try to guess - pls check if the following gives you what you need:
WITH t_new AS
(
SELECT PersIDOLD, PersIDNEW, RightsMUT,
SUM(gap) over(ORDER BY PersIDOLD, PersIDNEW) grp
FROM
(
SELECT h1.*,
CASE
WHEN h1.PersIDNEW = lag(h1.PersIDNEW)
over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
OR h1.PersIDOLD = lag(h1.PersIDOLD)
over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
THEN 0
ELSE 1
END gap
FROM HelpTable1 h1
)
)
SELECT PERSIDNEW, RIGHTSMUT
FROM t_new
WHERE PersIDNEW = 12 AND RightsMUT = 1
My solution:
WITH t_new AS
(
-- Alles durch gehen und
SELECT PersIDOLD, PersIDNEW, RightsMUT, SUM(gap) over(ORDER BY PersIDOLD, PersIDNEW) grp
FROM
(
SELECT h1.*,
CASE
WHEN h1.PersIDNEW = lag(h1.PersIDNEW) over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
OR h1.PersIDOLD = lag(h1.PersIDOLD) over(ORDER BY h1.PersIDOLD, h1.PersIDNEW)
THEN 0
ELSE 1
END gap
FROM LUTAXKT.HILFSTABELLE1UMSETZUNG h1
--WHERE h1.updateflag = 0
)
)
SELECT PersIDNEW, RightsMUT
FROM t_new
WHERE RightsMUT = 1 and
grp =
(
SELECT grp FROM t_new WHERE PersIDNEW = 12
)
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