开发者

c++: strange syntax in what() method of std::exception

When i am inheriting from std::exception in order to define my own exception type, i need to override the what() method, which has the following signature:

virtual const char* what() const throw();

This definitely looks strange to me, like if there were two method names in the signature. Is this some very specific syntax, like with pure virtual methods, e.g.:

virtual int开发者_运维技巧 method() const = 0;

or is this a feature, that could somehow be used in another context, too? And if so, for what could it be used?


It is called exception specifications. The throw() doesn't allow any exception to be thrown from inside this method throw(int) would only allow exceptions of type int to be thrown.

Exception specifications will be dropped in C++0x. This gives a very good explanation of the reasons.


virtual const char* what() const throw();

what() is a virtual constant method that returns pointer to const char and must not throw any exception. Not very strange method declaration :)

0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜