Is `auto int i` valid C++0x?

In answering this question the question arose as to whether the traditional C meaning of the keyword auto (automatic storage) is still valid in C++0x now that it means type deduction.

I remember that the old meaning of auto should remain where relevant but others disagreed.

auto char c = 42; // either compilation error or c = '*'

Looking at compilers I see the current division.

1. Old meani开发者_JS百科ng of auto is no longer allowed
   • VS10
   • g++
2. Old meaning of auto is used where relevant
   • Comeau

Do you know which is the correct behaviour?

No, it is not. In fact, §7.1.6.​4/3 gives the following example:

auto x = 5; // OK: x has type int
const auto *v = &x, u = 6; // OK: v has type const int*, u has type const int
static auto y = 0.0; // OK: y has type double
auto int r; // error: auto is not a storage-class-specifier

As you can see, it results in an error. §7.1.6.​5 pretty much seals the deal with:

A program that uses auto in a context not explicitly allowed in this section is ill-formed.