Django forms I cannot save picture file

i have the model:

class OpenCv(models.Model):
    created_by = models.ForeignKey(User, blank=True)
    first_name = models.CharField(('first name'), max_length=30, blank=True)
    last_name = models开发者_StackOverflow中文版.CharField(('last name'), max_length=30, blank=True)
    url = models.URLField(verify_exists=True)
    picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='jakido/avatar',blank=True, null= True)
    bio = models.CharField(('bio'), max_length=180, blank=True)
    date_birth = models.DateField(blank=True,null=True)
    domain = models.CharField(('domain'), max_length=30, blank=True, choices = domain_choices)
    specialisation = models.CharField(('specialization'), max_length=30, blank=True)
    degree = models.CharField(('degree'), max_length=30, choices = degree_choices)
    year_last_degree = models.CharField(('year last degree'), max_length=30, blank=True,choices = year_last_degree_choices)
    lyceum = models.CharField(('lyceum'), max_length=30, blank=True)
    faculty = models.ForeignKey(Faculty, blank=True,null=True)
    references = models.CharField(('references'), max_length=30, blank=True)
    workplace = models.ForeignKey(Workplace, blank=True,null=True)  

the form:

class OpencvForm(ModelForm):
class Meta:
      model = OpenCv
      fields = ['first_name','last_name','url','picture','bio','domain','specialisation','degree','year_last_degree','lyceum','references']

and the view:

 def save_opencv(request):
   if request.method == 'POST':
    form = OpencvForm(request.POST, request.FILES)
   # if 'picture' in request.FILES:
    file = request.FILES['picture']
    filename = file['filename']
    fd = open('%s/%s' % (MEDIA_ROOT, filename), 'wb')
fd.write(file['content'])
    fd.close() 
    if form.is_valid():
       new_obj = form.save(commit=False)
       new_obj.picture = form.cleaned_data['picture']
       new_obj.created_by = request.user

       new_obj.save()
       return HttpResponseRedirect('.')    
  else:
       form = OpencvForm()     
  return render_to_response('opencv/opencv_form.html', {
       'form': form,
       }, 
      context_instance=RequestContext(request))  

but i don't seem to save the picture in my database... something is wrong, and i can't figure out what :(

You don't make it easy to help you - you give no description of what actually happens.

However my guess is that you haven't included enctype="multipart/form-data" in your HTML form element.

I would recommend reading the file upload documentation - you're doing a few things manually here that could be handled for you by Django.

try: filename = file.name!

http://docs.djangoproject.com/en/dev/topics/http/file-uploads/

I've found the solution:

def save_opencv(request):
    if request.method == 'POST':
    form = OpencvForm(request.POST, request.FILES) 
    if form.is_valid():
       handle_uploaded_file(request.FILES['picture'])
       new_obj = form.save(commit=False)
       new_obj.created_by = request.user

       new_obj.save()
       return HttpResponseRedirect('.')    
   else:
       form = OpencvForm()     
  return render_to_response('opencv/opencv_form.html', {
       'form': form,
       }, 
      context_instance=RequestContext(request))  

and the handle_uploaded_file:

  def handle_uploaded_file(f):
     destination = open('root', 'wb+')
      for chunk in f.chunks():
      destination.write(chunk)
    destination.close()

Please review the indentation. Also, in models.py I have:

picture = models.ImageField(help_text=('Upload an image (max %s kilobytes)' %settings.MAX_PHOTO_UPLOAD_SIZE),upload_to='root',blank=True)

Please be careful that I am saving it to root, which means THE ROOT OF MY SITE , not anything related to the computer file organisation. Also, there is not big deal about the code, the deal is the path - I really didn't understand how to set it at first. Anyway, hope it helps you.

Your error is here:

filename = file['filename']

It should be:

filename = file.name

Change this:

fd.write(file['content']) 

to

fd.write(file.read())