C# Getting Just Date From Timestamp

If I have a timestamp in the form: yyyy-mm-dd hh:mm:ss:mmm

How can I just extract the date from the timestamp?

For instan开发者_如何学Goce, if a timestamp reads: "2010-05-18 08:36:52:236" what is the best way to just get 2010-05-18 from it.

What I'm trying to do is isolate the date portion of the timestamp, define a custom time for it to create a new time stamp. Is there a more efficient way to define the time of the timestamp without first taking out the date, and then adding a new time?

DateTime.Parse("2010-05-18 08:36:52:236").ToString("yyyy-MM-dd");

You should use the DateTime type:

DateTime original = DateTime.Parse(str);
DateTime modified = original.Date + new TimeSpan(13, 15, 00);
string str = modified.ToString("yyyy-MM-dd HH:mm:ss:fff");

Your format is non-standard, so you'll need to call ParseExact instead of Parse:

DateTime original = DateTime.ParseExact(str, "yyyy-MM-dd HH:mm:ss:fff", CultureInfo.InvariantCulture);

You could use substring:

"2010-05-18 08:36:52:236".Substring(0, 10);

Or use ParseExact:

DateTime.ParseExact("2010-05-18 08:36:52:236", 
                    "yyyy-MM-dd HH:mm:ss:fff", 
                    CultureInfo.InvariantCulture)
        .ToString("yyyy-MM-dd");

DateTime date;
if (DateTime.TryParse(dateString, out date))
{
   date = date.Date; // Get's the date-only component.
   // Do something cool.
}
else
{
   // Flip out because you didn't get a real date.
}

Get the .Date member on the DateTime

DateTime date = DateTime.Now;
DateTime midnightDate = date.Date;

use it like this:

var x = DateTime.Now.Date; //will give you midnight today

x.AddDays(1).AddTicks(-1); //use these method calls to modify the date to whats needed.

The best (and fastest) way to do this is to convert the date to an integer as the time part is stored in the decimal part.

Try this:

select convert(datetime,convert(int, @yourdate))

So you convert it to an integer and then back to a data and voila, time part is gone.

Of course subtracting this result from the original value will give you the time part only.