how to calculate count in sql?

I have the following table:

memberid  
2
2
3
4
3

...and I want the following result:

memberid   开发者_高级运维 count
2           2
3           1    ---Edit by gbn: do you mean 2?
4           1

I was attempting to use:

  SELECT MemberID, 
         COUNT(MemberID) 
    FROM YourTable 
GROUP BY MemberID

...but now I want find which record which has maximum count. IE:

memberid   count
2          2

SELECT memberid, COUNT(*) FROM TheTable GROUP BY memberid

Although, it won't work for your desired output because you have "memberid = 3" twice.

Edit: After late update to question...

SELECT TOP 1 WITH TIES    --WITH TIES will pick up "joint top". 
    memberid, COUNT(*)
FROM
    TheTable 
GROUP BY 
    memberid
ORDER BY
    COUNT(*) DESC

SELECT MemberID, COUNT(MemberID) FROM YourTable GROUP BY MemberID

What if there is a tie (or more) for the max? Do you want to display one or all?

This is how I would do this

SELECT memberid, COUNT(1)
FROM members
GROUP BY memberid
HAVING COUNT(1) = (
            SELECT MAX(result.mem_count)
            FROM (  
                SELECT memberid, COUNT(1) as mem_count
                FROM members
                GROUP BY memberid
            ) as result
          )

I would love to see a more efficient approach though.

Do it like this:

SELECT memberid, COUNT(memberid) AS [count] FROM [Table] GROUP BY memberid

This should do the trick with no subselects required:

select top 1 memberid, COUNT(*) as counted 
from members
group by memberid
order by counted desc

Can be done quite easy:

SELECT TOP 1 MemberId, COUNT(*) FROM YourTable GROUP BY MemberId ORDER By 2 DESC

I believe the original poster requested 2 result sets.

The only way I know of to get this (in SQL Server) is to dump the original records into a temp table and then do a SELECT and MAX on that. I do welcome an answer that requires less code!

-- Select records into a temp table
SELECT
    Table1.MemberId
    ,CNT = COUNT(*)
INTO #Temp
FROM YourTable AS Table1
GROUP BY Table1.MemberId
ORDER BY Table1.MemberId

-- Get original records
SELECT * FROM #Temp

-- Get max. count record(s) 
SELECT 
    Table1.MemberId
    ,Table1.CNT
FROM #Temp AS Table1
INNER JOIN (
    SELECT CNT = MAX(CNT)
    FROM #Temp
) AS Table2 ON Table2.CNT = Table1.CNT

-- Cleanup 
DROP TABLE #Temp

How about this query:

SELECT TOP 1 MemberID, 
       COUNT(MemberID) 
FROM YourTable 
GROUP BY MemberID
ORDER by count(MemberID) desc

SELECT count(column_name) FROM your_table;

You need to use a subselect:

SELECT MemberID, MAX(Count) FROM
    (SELECT MemberID, COUNT(MemberID) Count FROM YourTable GROUP BY MemberID)
GROUP BY MemberID

The second group by is needed to return both, the count and the MemberID.