开发者

java Processbuilder - exec a file which is not in path on OS X

Okay i'm trying to make ChucK available in exported Processing sketches, i.e. if i export an app from Processing, the ChucK VM binary will be executed from inside the app. So as a user of said app you don't need to worry about ChucK being in your path at all.

Right now i'm generating and executing a bash script file, but this way i don't get any console output from ChucK back into Processing:

#!/bin/bash
cd "[to where the Chuck executable is located]"
./chuck --kill
killall chuck # just to make sure
./chuck chuckScript1.ck cuckScriptn.ck

then

Process p = Runtime.getRuntime().exec("chmod 777 "+scriptPath);
p = Runtime.getRuntime().exec(scriptPath);

This works but i want to run ChucK directly from Processing instead, but can't get it to execute:

String chuckPath = "[folder in which the chuck executable is located]"
ProcessBuilder builder = new ProcessBuilder
                              (chuckPath+"/chuck", "test.ck");

        final Process process = builder.start();
        InputStream is = process.getInputStream();
开发者_C百科        InputStreamReader isr = new InputStreamReader(is);
        BufferedReader br = new BufferedReader(isr);
        String line;
        while((line = br.readLine()) != null) println(line);
        println("done chuckin'! exitValue: " + process.exitValue());

Sorry if this is newbie style :D


ProcessBuilder builder = new ProcessBuilder
                              (chuckPath+"/chuck", chuckPath+"/test.ck");

the args all need an absolute path.

0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜