How can I trim certain characters from a string in sql?

I would like to trim all special characters from a string in SQL. I've seen a bunch of people who use substring methods to remove a certain amount of characters, but in this case 开发者_StackOverflow中文版the length on each side of the string is unknown.

Anyone know how to do this?

use replace function will help you

i mean to say when you want to remove special char replace this space' ' by using replace function

more about replace : http://technet.microsoft.com/en-us/library/ms186862.aspx

In MS SQL, this will remove all plus signs:

SELECT REPLACE(theField, '+', '') FROM theTable

Is that the sort of thing you need?

I wrote this function for LEFT trimming any char

CREATE FUNCTION TRIMCHAR
(
    -- Add the parameters for the function here
     @str varchar(200) ,  @chartotrim varchar(1)
)
RETURNS  varchar(200)  
AS
BEGIN



DECLARE @temp varchar(2000)

SET  @temp = @str   

WHILE  CHARINDEX (  @chartotrim  ,  @temp )  =1
BEGIN


SET @temp  = RIGHT( @temp , LEN(@temp)-1) 

END 


RETURN   @temp 

END
GO

USE [YourDataBase]
GO
/****** Object:  UserDefinedFunction [Accounts].[fn_CurrentFeeorArrears]    Script Date: 02/18/2014 12:54:15 ******/
/*****Developed By rameez****/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [FN_REMOVE_SPECIAL_CHARACTER] 
(  
 @INPUT_STRING varchar(300))
RETURNS VARCHAR(300)
AS 
BEGIN

--declare @testString varchar(100),
DECLARE @NEWSTRING VARCHAR(100) 
-- set @teststring = '@ram?eez(ali)'
 SET @NEWSTRING = @INPUT_STRING ; 
With SPECIAL_CHARACTER as
(
--SELECT '>' as item
--UNION ALL 
--SELECT '<' as item
--UNION ALL 
--SELECT '(' as item
--UNION ALL 
--SELECT ')' as item
--UNION ALL 
--SELECT '!' as item
--UNION ALL 
--SELECT '?' as item
--UNION ALL 
--SELECT '@' as item
--UNION ALL 
--SELECT '*' as item
--UNION ALL 
--SELECT '%' as item
--UNION ALL 
SELECT '$' as item
 )
SELECT @NEWSTRING = Replace(@NEWSTRING, ITEM, '') FROM SPECIAL_CHARACTER  
return @NEWSTRING 
END
select dbo.[FN_REMOVE_SPECIAL_CHARACTER] ('r$@ameez')