Passing an array as a function parameter in JavaScript
I'd like to call a function using an array as parameters:
const x = ['p0', 'p1', 'p2'];
call_me(x[0], x[1], x[2]); // I don't like it
function call_me (param0, param1, param2 ) {
// ...
}
Is th开发者_如何学编程ere a better way of passing the contents of x into call_me()?
const args = ['p0', 'p1', 'p2'];
call_me.apply(this, args);
See MDN docs for Function.prototype.apply().
If the environment supports ECMAScript 6, you can use a spread argument instead:
call_me(...args);
Why don't you pass the entire array and process it as needed inside the function?
var x = [ 'p0', 'p1', 'p2' ];
call_me(x);
function call_me(params) {
for (i=0; i<params.length; i++) {
alert(params[i])
}
}
In ES6 standard there is a new spread operator ... which does exactly that.
call_me(...x)
It is supported by all major browsers except for IE.
The spread operator can do many other useful things, and the linked documentation does a really good job at showing that.
Assuming that call_me is a global function, so you don't expect this to be set.
var x = ['p0', 'p1', 'p2'];
call_me.apply(null, x);
As @KaptajnKold had answered
var x = [ 'p0', 'p1', 'p2' ];
call_me.apply(this, x);
And you don't need to define every parameters for call_me function either.
You can just use arguments
function call_me () {
// arguments is a array consisting of params.
// arguments[0] == 'p0',
// arguments[1] == 'p1',
// arguments[2] == 'p2'
}
While using spread operator we must note that it must be the last or only parameter passed. Else it will fail.
function callMe(...arr){ //valid arguments
alert(arr);
}
function callMe(name, ...arr){ //valid arguments
alert(arr);
}
function callMe(...arr, name){ //invalid arguments
alert(arr);
}
If you need to pass an array as the starting argument you can do:
function callMe(arr, name){
let newArr = [...arr];
alert(newArr);
}
Function arguments may also be Arrays:
function foo([a,b,c], d){
console.log(a,b,c,d);
}
foo([1,2,3], 4)of-course one can also use spread:
function foo(a, b, c, d){
console.log(a, b, c, d);
}
foo(...[1, 2, 3], 4)Note this
function FollowMouse() {
for(var i=0; i< arguments.length; i++) {
arguments[i].style.top = event.clientY+"px";
arguments[i].style.left = event.clientX+"px";
}
};
//---------------------------
html page
<body onmousemove="FollowMouse(d1,d2,d3)">
<p><div id="d1" style="position: absolute;">Follow1</div></p>
<div id="d2" style="position: absolute;"><p>Follow2</p></div>
<div id="d3" style="position: absolute;"><p>Follow3</p></div>
</body>
can call function with any Args
<body onmousemove="FollowMouse(d1,d2)">
or
<body onmousemove="FollowMouse(d1)">
you can use the spread syntax
for example:
function print(...inpu){
console.log(...inpu)
}
var arry = ['p0','p1','p2']
print(...arry)here is the link: modzilla spread syntax refrence document
you can use spread operator in a more basic form
[].concat(...array)
in the case of functions that return arrays but are expected to pass as arguments
Example:
function expectArguments(...args){
return [].concat(...args);
}
JSON.stringify(expectArguments(1,2,3)) === JSON.stringify(expectArguments([1,2,3]))
The answer was already given, but I just want to give my piece of cake. What you want to achieve is called method borrowing in the context of JS, that when we take a method from an object and call it in the context of another object. It is quite common to take array methods and apply them to arguments. Let me give you an example.
So we have "super" hashing function which takes two numbers as an argument and returns "super safe" hashed string:
function hash() {
return arguments[0]+','+arguments[1];
}
hash(1,2); // "1,2" whoaa
So far so good, but we have little problem with the above approach, it is constrained, only works with two numbers, that is not dynamic, let's make it work with any number and plus you do not have to pass an array (you can if you still insist). Ok, Enough talk, Let's fight!
The natural solution would be to use arr.join method:
function hash() {
return arguments.join();
}
hash(1,2,4,..); // Error: arguments.join is not a function
Oh, man. Unfortunately, that won’t work. Because we are calling hash(arguments) and arguments object is both iterable and array-like, but not a real array. How about the below approach?
function hash() {
return [].join.call(arguments);
}
hash(1,2,3,4); // "1,2,3,4" whoaa
The trick is called method borrowing.
We borrow a join method from a regular array [].join. And use [].join.call to run it in the context of arguments.
Why does it work?
That’s because the internal algorithm of the native method arr.join(glue) is very simple.
Taken from the specification almost “as-is”:
Let glue be the first argument or, if no arguments, then a comma ",".
Let result be an empty string.
Append this[0] to result.
Append glue and this[1].
Append glue and this[2].
…Do so until this.length items are glued.
Return result.
So, technically it takes this and joins this[0], this[1] …etc together. It’s intentionally written in a way that allows any array-like this (not a coincidence, many methods follow this practice). That’s why it also works with this=arguments.
There's a better way using JSON not an Array!
// Call a function with a Json Key / Value Pair:
sendMail({param1: p1, param2: p2});
// Function definition and usage of value pairs:
function sendMail(data){
var parameter1 = data.param1;
var parameter2 = data.param2;
}
加载中,请稍侯......
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