select distinct col1 with min(col2) and max(col3) from table

My table looks like this with duplicates in col1

col1,      col2,      col3,      col4
1,            1,            0,            a
1,            2,            1,            a
1,            3,            1,            a
2,            4,            1,            b
3,            5,            0,            c  

I want to select distinct col1 with max (col3) and min(col2); so result set will be:

col1,      col2,      col3,      col4
1,            2,            1,            a
2,            4,     开发者_运维问答       1,            b
3,            5,            0,            c

I have a solution but looking for best ideas?

SELECT col1, MAX(col3) AS col3, MIN(col2) AS col2, MAX(col4) AS col4
FROM MyTable
GROUP BY col1;

You showed in your example that you wanted a col4 included, but you didn't say which value you want. You have to put that column either in an aggregate function or in the GROUP BY clause. I assumed that taking the max for the group would be acceptable.

update: Thanks for the clarification. You're asking about a variation of the greatest-n-per-group problem that comes up frequently on Stack Overflow. Here's my usual solution:

SELECT t1.*
FROM mytable t1
LEFT OUTER JOIN mytable t3
 ON t1.col1 = t3.col1 AND t1.col3 < t3.col3
WHERE t3.col1 IS NULL;

In English: show me the row (t1) for which no row exists with the same col1 and a greater value in col3. Some people write this using a NOT EXISTS subquery predicate, but I prefer the JOIN syntax.

Here's the output from my test given your example data:

+------+------+------+------+
| col1 | col2 | col3 | col4 |
+------+------+------+------+
|    1 |    2 |    1 | a    |
|    1 |    3 |    1 | a    |
|    2 |    4 |    1 | b    |
|    3 |    5 |    0 | c    |
+------+------+------+------+

Notice that there are two rows for col1 value 1, because both rows satisfy the join condition; no other row exists with a greater value in col3.

So we need to add another condition to resolve the tie. You want to compare to rows with a lesser value in col2 and if no such rows exist, then we've found the row with the least value in col2.

SELECT t1.*
FROM MyTable t1
LEFT OUTER JOIN MyTable t3
 ON t1.col1 = t3.col1 AND t1.col3 < t3.col3
LEFT OUTER JOIN MyTable t2
 ON t1.col1 = t2.col1 AND t1.col3 = t2.col3 AND t1.col2 > t2.col2
WHERE t2.col1 IS NULL AND t3.col1 IS NULL; 

Here's the output from my test given your example data:

+------+------+------+------+
| col1 | col2 | col3 | col4 |
+------+------+------+------+
|    1 |    2 |    1 | a    |
|    2 |    4 |    1 | b    |
|    3 |    5 |    0 | c    |
+------+------+------+------+

PS: By the way, it's customary on Stack Overflow to edit your original question and add detail, instead of adding answers to your own question that only clarify the question. But I know some actions aren't available to you until you have more than 1 reputation point.