Codeigniter: URI segments
How do I create an if statement saying something like this? Basically, how do you use the URI class to determine if there is a value in any segment?
$segment = value_of_any_segme开发者_StackOverflownt;
if($segment == 1{
do stuff
}
I know this is pretty elementary, but I don't totally understand the URI class...
Your question is a little unclear to me, but I'll try to help. Are you wondering how to determine if a particular segment exists or if it contains a specific value?
As you are probably aware, you can use the URI class to access the specific URI segments. Using yoursite.com/blog/article/123
as an example, blog
is the 1st segment, article
is the 2nd segment, and 123
is the 3rd segment. You access each using $this->uri->segment(n)
You then can construct if statements like this:
// if segment 2 exists ("articles" in the above example), do stuff
if ($this->uri->segment(2)) {
// do stuff
}
// if segment 3 ("123" in the above example) is equal to some value, do stuff
if ($this->uri->segment(3) == $myValue) {
// do stuff
}
Hope that helps! Let me know if not and I can elaborate or provide additional information.
Edit:
If you need to determine if a particular string appears in any segment of the URI, you can do something like this:
// get the entire URI (using our example above, this is "/blog/article/123")
$myURI = $this->uri->uri_string()
// the string we want to check the URI for
$myString = "article";
// use strpos() to search the entire URI for $myString
// also, notice we're using the "!==" operator here; see note below
if (strpos($myURI, $myString) !== FALSE) {
// "article" exists in the URI
} else {
// "article" does not exist in the URI
}
A note regarding strpos() (from the PHP documentation):
This function may return Boolean FALSE, but may also return a non-Boolean value which evaluates to FALSE, such as 0 or "". Please read the section on Booleans for more information. Use the === operator for testing the return value of this function.
I hope my edit helps. Let me know if I can elaborate.
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