How to populate html combo box with mysql data
Please help, I'm having trouble loading mysql data on the combo box. The data that I'm loading is 1 column from a table. Here is my current code, and it crashed firefox for some reason:
<td colspan=”2″>Religion</TD>
<td>
<select name="REL" onClick="submitCboSemester();">
<?php
$query_disp="SELECT * FROM Religion ORDER BY RID";
$result_disp = mysql_query($query_disp, $conn);
while($query_data = mysql_fetch_array($result_disp))
{
?>
<option value="<? echo $query_data["RID"]; ?>"<?php if ($query_data["RID"]==$_POST['REL']) {?>selected<? } ?>><? echo $query_data["RELIGION"]; ?></option>
<? } ?>
</select>
</td>
The colu开发者_高级运维mn is RELIGION
and it ID is RID
How do I populate the combo box with all the data in the column RELIGION
Chances are, you don't have short_open_tag
enabled in php.ini
, this is probably what was causing your code to fail.
Also, you should output selected="selected"
, not just selected
Try this:
<td colspan=”2″>Religion</TD>
<td>
<select name="REL" onClick="submitCboSemester();">
<?php
$query_disp="SELECT * FROM Religion ORDER BY RID";
$result_disp = mysql_query($query_disp, $conn);
while($query_data = mysql_fetch_array($result_disp))
{
?>
<option value="<?php echo $query_data["RID"]; ?>"<?php if ($query_data["RID"]==$_POST['REL']) {?> selected="selected"<? } ?>><?php echo $query_data["RELIGION"]; ?></option>
<? } ?>
</select>
</td>
<html>
<title>
demo </title>
<body>
<?
// Load field datas into List box
$cn=mysql_connect("localhost",root) or die("Note: " . mysql_error());
echo "Conn ok<br>";
$res=mysql_select_db("test",$cn) or die("Note: " . mysql_error());
echo " Database opened<br>";
$q="insert into usha2 (`sno`, `city name`) values (NULL, 'Nagercoil');";
//$q="INSERT into `test`.`usha2` (`sno`, `city name`) VALUES (NULL, 'Delhi');";
$res=mysql_query($q) or die("Note: " . mysql_error());
echo " record inserted<br>";
$res=mysql_query("select * from usha2;") or die("Note: " . mysql_error());
echo " qry executed<br>";
?>
<select name="pno" size=1>
<?
while($ri = mysql_fetch_array($res))
{
echo "<option value=" .$ri['city name'] . ">" . $ri['city name'] . "</option>";
}
echo "</select> "
?>
</body>
Extract the data before displaying it !
And also, use the PHP Alternative Syntax when mixing PHP & HTML :
<?php
$query_disp="SELECT * FROM Religion ORDER BY RID";
$result_disp = mysql_query($query_disp, $conn);
$options = array();
while ($query_data = mysql_fetch_array($result_disp)) {
$options[$query_data["RID"]] = $query_data["RELIGION"];
}
?>
<select name="REL" onClick="submitCboSemester();">
<?php foreach ($options as $key => $value) : ?>
<?php $selected = ($key == $_POST['REL']) ? 'selected="selected"' : ''; ?>
<option value="<?php echo $key ?>" <?php echo $selected ?>>
<?php echo $value ?>
</option>
<?php endforeach; ?>
</select>
Looks like there is no space between the end of your value and the selected
.
When you pull the data from your database you should use the following format as the format you are currently using is being phase out as MySqli advances
$religion = $db->query("SELECT Religion FROM TableName ORDER BY RID");
$db is a connection to the database created as such
$db = new Mysqli($server, $username, $password, $database);
Just set the variable to the correct value.
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