Android Shape Line
I have the following code:
<shape xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="line">
<stroke android:width="1dp"/>
<size android:height="1dp" />
<solid android:color="#FFF"/>
</shape>
<LinearLayout
android:开发者_如何学JAVAlayout_width="fill_parent"
android:layout_height="wrap_content"
android:background ="@drawable/line"/>
I have two questions:
- Why the line is black instead white? I have tried putting it inside a ImageView but the result is the same.
- How can i set the opacity of the shape?
1) In order to set the color of the line, you need to define android:color
on the <stroke>
. The <solid>
element is for the background.
2) You can set the opacity of the shape by using color values with an alpha layer, aka #ARGB. In your case, maybe #7FFF.
The simplest example of the line for 2 density pixels with black color. Just save the xml in drawable folder: res/drawable/shape_black_line.xml
<?xml version="1.0" encoding="utf-8"?>
<shape
xmlns:android="http://schemas.android.com/apk/res/android"
android:shape="line">
<stroke
android:width="1dp"
android:color="#000000" />
<size android:height="2dp" />
</shape>
Use LinearLayout and background to show the line.
<LinearLayout
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:background="@drawable/divider">
</LinearLayout>
I hope this helped.
A tricky way can be like this:
1) Add a View where you want have a line.
2) set android:background
to a hex value that you can set both color and opacity.
For example:
<View
android:layout_width="match_parent"
android:layout_height="6dp"
android:background="#77f27123"
android:orientation="vertical" />
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