Write a program that allows the user to enter a string and then prints the letters of the String separated by comma
The output is always a String, for example H,E,L,L,O,
. How could I limit the commas? I want the commas only between letters, for example H,E,L,L,O
.
import java.util.Scanner;
import java.lang.String;
public class forLoop开发者_Python百科
{
public static void main(String[] args)
{
Scanner Scan = new Scanner(System.in);
System.out.print("Enter a string: ");
String Str1 = Scan.next();
String newString="";
String Str2 ="";
for (int i=0; i < Str1.length(); i++)
{
newString = Str1.charAt(i) + ",";
Str2 = Str2 + newString;
}
System.out.print(Str2);
}
}
Since this is homework I'll help you out a little without giving the answer:
If you want the output to only be inbetween letters IE: A,B,C instead of A,B,C, which is what I imagine you are asking about. Then you need to look at your for loop and check the boundary conditions.
The easiest way I see is :
public static void main(String[] args) {
Scanner Scan = new Scanner(System.in);
System.out.print("Enter a string: ");
String Str1 = Scan.nextLine();
String newString="";
String Str2 ="";
for (int i=0; i < Str1.length()-1; i++)
{
newString = Str1.charAt(i) + ",";
Str2 = Str2 + newString;
}
Str2 = Str2 + Str1.charAt(Str1.length()-1);
System.out.println(Str2);
}
The output it will give is :
run:
Enter a string: Hello world
H,e,l,l,o, ,w,o,r,l,d
BUILD SUCCESSFUL (total time: 5 seconds)
Though I will highly recommend learning regular expression as suggested by @Roman. Till then this will do the trick. :)
Try regular expressions:
String input = scanner.next();
String output = input.replaceAll(".", "$0,");
With spaces it would be a bit easier since you don't need to abandon last 'odd' comma:
output = output.substring (0, ouput.length() - 2);
When you've figured out the loop-solution, you could try the following ;)
System.out.println(Arrays.toString("HELLO".toCharArray()).replaceAll("[\\[ \\]]", ""));
Just don't append the comma when the last item of the loop is to be appended. You have the item index by i
and the string length by Str2.length()
. Just do the primary school math with a lesser-than or a greater-than operator in an if
statement.
The following snippet should be instructive. It shows:
- How to use
StringBuilder
for building strings - How to process each
char
in aString
using an explicit index- How to detect if it's the first/last iteration for special processing
String s = "HELLO";
StringBuilder sb = new StringBuilder();
for (int i = 0; i < s.length(); i++) {
char ch = s.charAt(i);
if (i == 0) { // first
sb.append("(" + ch + ")");
} else if (i == s.length() - 1) { // last
sb.append("<" + ch + ">");
} else { // everything in between
sb.append(Character.toLowerCase(ch));
}
}
System.out.println(sb.toString());
// prints "(H)ell<O>"
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