php - regex- preg_replace - space after line-break!
still on regex! i want learn it but i'm still crashing the head into my key开发者_开发问答bord! ;-)
ok very trivial for you, i'm sure!
Assuming i have this sting, the \s
is where the space actualy is... \n
where linebreak is..
EDITED:
OTHERFIELD: Other text here...`\n`
DESCRIPTION: The quick brown fox jum`\s\n`
`\s`ps over the lazy dog
OTHERFIELD: Other text here...`\n`
just for explanation:
each line always start with an UPPERCASE word followed by a colon!
so the only way i have for split each line is by it's last \n
for this reason i can't remove it!
then i'm preg_splitting each cleaned line with this regex
/$\R?[^A-Z:]*/m
that give me an array like this:
[DESCRIPTION] => The quick brown fox jumps over the lazy dog
now, what i need to do is remove All the space after the A-Z:
that i have achieved by this regex: /\s+(?![A-Z:])/m
that produce this result
DESCRIPTION: The quick brown fox jum ps over the lazy dog
as you can see it leave the space between jum
and ps
how to have a result like this?
DESCRIPTION: The quick brown fox jumps over the lazy dog
thank's for the time!
Try this regular expression:
/\s+\n\s+/
This will match the whitespace only if it’s surrounding a line feed character. You may need to adjust the quantifiers to fit your actual data.
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