jquery stop image rotation on mouseover, start on mouseout / hover
I have built a jQuery rotator to rotate through 3 divs and loop them. I would like to add the functionality on mouse over to "freeze" the current div and then start again on mouse out.
I've thought about setting a variable to false at the start of the function and setting it true when it's on it's current frame but I've got my self a bit confused.
I've also tried to use the hover function but when using the in and out handlers, I'm confused as to how to stop, restart the animation.
function ImageRotate() {
var CurrentFeature = "#container" + featureNumber;
$(CurrentFeature).stop(false, true).delay(4500).animate({'top' : '330px'}, 3000);
var featureNumber2 = featureNumber+1;
if ( featureNumber == numberOfFeatures) {featureNumber2 = 1}
var NewFeature = "#container" + featureNumber2;
$(NewFeature).stop(false, true).delay(4500).animate({'top' : '0px'}, 3000);
var featureNumber3 = featureNumber-1;
if ( featureNumber == 1) {featureNumber3 = numberOfFeatures};
var OldFeature = "#container" + featureNumber3;
$(OldFeature).stop(false, true).delay(4500).css('top' , '-330px');
set开发者_JAVA技巧Timeout('if (featureNumber == numberOfFeatures){featureNumber = 1} else {featureNumber++}; ImageRotate2()', 7500)};
Any help would be greatly appreciated!! Thanks, Matt
If you were to add this code:
var timerId = null;
function startRotation() {
if (timerId) {
return;
}
timerId = setInterval('if (featureNumber == numberOfFeatures){featureNumber = 1} else {featureNumber++}; ImageRotate2()', 7500);
}
function stopRotation() {
if (!timerId) {
return;
}
clearInterval(timerId);
timerId = null;
}
and replace the last line of your code block with a simple call to startRotation();
, then you could call stopRotation
and startRotation
when the mouse hovers over/leaves your element:
$('your-element-selector').hover(stopRotation, startRotation);
It's not clear what you are trying to do with the three divs without seeing the HTML and more code, so I think a basic example might help you better (demo).
HTML
<div class="test">image: <span></span></div>
Script
$(document).ready(function(){
var indx = 0, loop, numberOfFeatures = 5;
function imageRotate(){
indx++;
if (indx > numberOfFeatures) { indx = 1; }
$('.test span').text(indx);
loop = setTimeout( imageRotate , 1000 );
}
imageRotate();
$('.test').hover(function(){
clearTimeout(loop);
}, function(){
imageRotate();
});
})
changed things up a little bit, here is how I ended up doing it. `
var animRun = false;
var rotateHover = false;
function startRotation() {
rotateHover = false;
ImageRotate();
}
function stopRotation() {
rotateHover = true;
clearTimeout();
}
function ImageRotate() {
if (rotateHover == false){
animRun = true;
var CurrentFeature = "#container" + featureNumber;
$(CurrentFeature).stop(false, true).animate({'top' : '330px'}, featureDuration, function(){animRun = false;});
var featureNumber2 = featureNumber+1;
if ( featureNumber == numberOfFeatures) {featureNumber2 = 1}
var NewFeature = "#container" + featureNumber2;
$(NewFeature).stop(false, true).animate({'top' : '0px'}, featureDuration); /* rotate slide 2 into main frame */
var featureNumber3 = featureNumber-1;
if ( featureNumber == 1) {featureNumber3 = numberOfFeatures};
var OldFeature = "#container" + featureNumber3;
$(OldFeature).stop(false, true).css('top' , '-330px'); /*bring slide 3 to the top*/
//startRotation();
setTimeout('if (featureNumber == numberOfFeatures){featureNumber = 1} else {featureNumber++}; if (rotateHover == false){ImageRotate2()};', featureDelay);
};
};
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