JS Error:Cannot call method of null
I have the following method in a js file in ASP.Net web project. This method is giving the error Cannot call method 'split' of null
function loadUser_InfoCallBack(res)
{
var ret=res.value;
var senderGUID = ret.split(';')[0];
var senderText = ret.split(';')[1];
if(senderGUID.Length>0)
{
$('hiddenSender.value')=senderGUID;
$('hiddenText.value')=senderText;
}
}
Can anybody suggest the reasons for this error..
where the code for the getOwnerInfo method is below
[AjaxPro.AjaxMethod(AjaxPro.HttpSessionStateRequirement.ReadWrite)]
public string getOwnerInfo()
{
string strReturn = ";";
if (Session["User_GUID"] != null)
{
string strUserGUID = Session["User_GUID"开发者_如何学JAVA].ToString();
string strIndGUID = "";
string strIndName = "";
//Initialize Connection String
cns = DAL360.Common.getConnection(HttpContext.Current.Session["Server"].ToString(), HttpContext.Current.Session["Database"].ToString());
DAL360.std_UserRepositoryArtifacts.std_UserRepository userRep = new DAL360.std_UserRepositoryArtifacts.std_UserRepository(cns);
std_User user = userRep.Getstd_UserByusr_GUID(new Guid(strUserGUID));
DAL360.std_IndividualRepositoryArtifacts.std_IndividualRepository indRep = new DAL360.std_IndividualRepositoryArtifacts.std_IndividualRepository(cns);
std_Individual ind = indRep.Getstd_IndividualByind_GUID(new Guid(user.usr_ind_GUID.ToString()));
if (ind != null)
{
strIndGUID = ind.ind_GUID.ToString();
strIndName = ind.ind_Prefix + " " + ind.ind_FirstName + " " + ind.ind_MiddleName + " " + ind.ind_LastName;
DAL360.std_IndividualAddressRepositoryArtifacts.std_IndividualAddressRepository iadRep = new DAL360.std_IndividualAddressRepositoryArtifacts.std_IndividualAddressRepository(cns);
List<std_IndividualAddress> iadList = iadRep.GetAllFromstd_IndividualAddressByIndGUID(ind.ind_GUID);
if (iadList != null && iadList.Count > 0)
{
std_IndividualAddress iad = iadList[0];
strIndName += " (" + iad.iad_City + ", " + iad.iad_State + ")";
}
}
strReturn = strIndGUID + ";" + strIndName;
}//end if statement
return strReturn;
}
And this method is in the code behind page of frmHome.aspx page. And I get the error when i try to open the page frmHome.aspx
The most probable reason will be that there won't be any element res. So taking res.value
will return null, and split is expecting a string.
精彩评论