MySQL date query only returns one year, when multiple exist
I'm a part-time designer/developer with a part-time photography business. I've got a database of photos with various bits of metadata attached. I want to query the database and return a list of the years that photos were taken, and the quantity of photos that were taken in that year.
In short, I wa开发者_开发知识库nt a list that looks like this:
2010 (35 photos)
2009 (67 photos)
2008 (48 photos)
Here's the query I'm using:
SELECT YEAR(date) AS year, COUNT(filename) as quantity FROM photos WHERE visible='1' GROUP BY 'year' ORDER BY 'year' DESC
Instead of churning out all the possible years (the database includes photos from 2010-2008), this is the sole result:
2010 (35 photos)
I've tried a lot of different syntax but at this point I'm giving in and asking for help!
Don't single-quote year
.
That is telling MySQL that year
is a string; which it isn't.
In addition, don't use an alias in the GROUP BY
.
Try this:
SELECT YEAR(date) AS year, COUNT(filename) as quantity
FROM photos
WHERE visible='1'
GROUP BY YEAR(date)
ORDER BY YEAR(date) DESC
Edit:
In most RDBMSes the SELECT
clause is interpreted last.
So we cannot use a column alias in other clauses of that particular query.
T-SQL Solution:
SELECT
[text] =
cast(year(date) as varchar) + ' ('+cast(count(filename) as varchar) +
'photo'+case when count(filename)>1 then 's' else '' end + ')'
,
[year] = year(date)
FROM photos
WHERE visible='1'
GROUP BY YEAR(date)
ORDER BY YEAR(date) DESC
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