Find folder path based on each character of a word and use grep on selected file
I want to run the code below and use grep to search for "LARGE_NAME" inside a file that is in a path that needs yet to be determined. Important:
- Both file and folder names are just 1 distinct letter of the alphabet [a-z];
- Files have no file extension. Example: "$dir/$letter1/$letter2", $letter2 is the file;
- I know that I found the path if there is no more subfolders to be searched.
.
./query.sh LARGE_NAME
The final file could be in:
$dir/$letter1
$dir/$letter1/$letter2
$dir/$letter1/$letter2/$letter3/
.... so on
Where:
$letter1 = L
$letter2 = A
$letter3 = R
.... so on
I want to optimize my code that works but have too many nested IFs. Below is an example with just 3 letter search:
query.sh file:
#!/opt/homebrew/bin/bash
dir=$( cd "$( dirname "${BASH_SOURCE[0]}" )" && pwd )
letter1=$(echo ${1,,}|cut -b1)
if [ -f "$dir/$letter1" ]; then
grep -ai "^$1&quo开发者_Python百科t; "$dir/$letter1"
else
letter2=$(echo ${1,,}|cut -b2)
if [ -f "$dir/$letter1/$letter2" ]; then
grep -ai "^$1" "$dir/$letter1/$letter2"
else
letter3=$(echo ${1,,}|cut -b3)
if [ -f "$dir/$letter1/$letter2/$letter3" ]; then
grep -ai "^$1" "$dir/$letter1/$letter2/$letter3"
fi
fi
fi
How can I rewrite my code to search for up to 50 sub folders until it finds the last/final one with the file I want to grep?
So build the path cummulatively, one slash and letter at a time.
input=${1,,}
path="$dir"
for ((i = 0; i < ${#input}; ++i)); do
letter=${input:i:1}
path="$path/$letter"
if [[ -f "$path" ]]; then
grep -ai "^$1" "$path"
fi
done
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