Grouping XSLT nodes via transformation dynamically

I'm trying to create a page like this via XSLT transformation.

Pages

• page1
• page2

Links

• link1
• link2

Here is the xml

<siteMenu>
  <Pages>
    <title>page1</title>
  </Pages>
  <Pages>
    <title>page2</title>
  </Pages>
  <Links>
    <title>link1</title>
  </Links>
  <Links>
    <title>link2</title>
  </Links>
</siteMenu>

I tried u开发者_开发问答sing

<xsl:for-each select="*"> and <xsl:for-each-group select="*" group-by="@v">

but that gives me every element, but how can i separate them out based on the parent node?

I also want to make it dynamic so that if I add another item in siteMenu, it would update the xslt appropriately.

So you want to group by node name. Not the best idea to store more than actual structure information in the XML nodes, but here you go:

<siteMenu>
  <Pages>
    <title>page1</title>
  </Pages>
  <Pages>
    <title>page2</title>
  </Pages>
  <Links>
    <title>link1</title>
  </Links>
  <Links>
    <title>link2</title>
  </Links>
  <Sites>
    <title>site1</title>
  </Sites>
  <Sites>
    <title>site2</title>
  </Sites>
</siteMenu>

and this XSLT 2.0 transformation (relevant fragment only):

<xsl:template match="siteMenu">
  <xsl:for-each-group select="*" group-by="name()">
    <xsl:sort select="name()" />
    <div>
      <h1><xsl:value-of-select="current-grouping-key()" /></h1>
      <ul>
        <xsl:for-each select="current-group()">
          <li><xsl:value-of select="title" /></li>
        </xsl:for-each>
      </ul>
    </div>
  </xsl:for-each-group>
</xsl:template>

or this XSLT 1.0 transformation (relevant fragment only):

<xsl:key name="kMenu" match="siteMenu/*" use="name()" />

<xsl:template match="siteMenu">
  <xsl:for-each select="*[
    generate-id() = generate-id(key('kMenu', name())[1])
  ]">
    <xsl:sort select="name()" />
    <div>
      <h1><xsl:value-of-select="name()" /></h1>
      <ul>
        <xsl:for-each select="key('kMenu', name())">
          <li><xsl:value-of select="title" /></li>
        </xsl:for-each>
      </ul>
    </div>
  </xsl:for-each-group>
</xsl:template>

Hint: You might want to think about using such an XML instead, this obviously matches your site structure better and you need no grouping to output it correctly.

<siteMenu>
  <section name="Pages">
    <title>page1</title>
    <title>page2</title>
  </section>
  <section name="Links">
    <title>link1</title>
    <title>link2</title>
  </section>
  <section name="Sites">
    <title>site1</title>
    <title>site2</title>
  </section>
</siteMenu>

You are selecting everything (*).

Use select="Pages" to select pages, and select="Links" for links.

Learn about XPath expressions here.

I would start with

<ul>
  <xsl:for-each select="//Pages">
    <li><xsl:value-of select="./title"/></li>
  </xsl:for-each>
</ul>

and continue from there.