A simple way to remove headers from XML files

I need remove non-xml tags from file generated by another program.

The file is some like this:

Executing Command - Blah.exe ...
-----Command Output-----
HTTP/1.1 200 OK
Connection: close
Content-Type: text/xml

<?xml version="1.0"?>
<testResults>
  <finalCounts>
    <right>7</right>
    <wrong>4</wrong>
    <ignores>0</ignores>
    <exceptions>0</exceptions>
  </finalCounts>
</testResults>

Exit-Code: 15

How to remove the non-xml text eas开发者_Python百科ily in java?

// getContent() returns the complete text to strip.
//
String s = getContent();

// Find the start of the XML content using the <?xml prefix.
//
int xmlIndex = s.indexOf( "<?xml" );

// Strip the non-XML header.
//
s = s.substring( xmlIndex );

// Find the last closing angle-bracket; should indicate end of the XML.
//
xmlIndex = s.lastIndexOf( ">" );

// Strip everything after the closing angle-bracket.
//
s = s.substring( 0, xmlIndex );

This looks like direct HTTP output... so just scanning for the first two consecutive line feeds (probably with carriage returns in front of them) will give you the end of the prefix you want to filter out.