Why are these lines being skipped? (java)
Here's the relevant bit of the source code:
class Dice
{
String name ;
int x ;
int[] sum ;
...
public Dice (String name)
{
this.name = name ;
this.x = 0 ;
this.sum = new int[7] ;
}
...
public static void main (String[] arg)
{
Dice a1 = new Dice ("a1") ;
printValues (a1) ;
}
public static void printDice (Dice Dice)
{
System.out.println (Dice.name) ;
System.out.println ("value: "+Dice.x) ;
printValues (Dice) ;
}
public static void printValues (Dice Dice)
{
for (int i = 0; i<Dice.sum.length; i++)
System.out.println ("#of "+i+"'s: "+Dice.sum[i]) ;
}
}
Here is the output:
#of 0's: 0
#of 1's: 0
#of 2's: 0
#of 3's: 0
#of 4's: 0
#of 5's: 0
#of 6's: 0
Why didn't these two lines execute inside printDice
:
System.out.println (Dice.name) ;
System.out.println ("value: "+Dice.x) ;
if they had then i would expect to see "a1" and "Value: 0" printed at the top of the row开发者_运维技巧s of #of
's
Probably because none of the code you posted actually calls printDice()
.
With the exception of the main()
method, none of your methods in your classes are magically invoked - they need to be invoked by some other code.
printDice()
is never called:
public static void main (String[] arg)
{
Dice a1 = new Dice ("a1") ;
printValues (a1) ; // You only call printValues
}
You are calling printValues where you probably mean to call printDice.
I'm not a Java master, but I think that you'd better avoid naming the parameters the same way as you name a class. When you write:
public static void printDice (Dice Dice) { /* ... */ }
you're walking on the thin ice, dude. Reading your code it's hard to know if you call the static methods or the instance ones. I have to admit that i was surprised that Java allows something like that as it seems to be very dangerous and hard to understand when reading. In a free time - while not coding - read some Uncle Bob's texts ;) Peace!
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