Return a pointer to a char array in C

I've seen a lot of questions on that on StackOverflow, but reading the answers did not clear that up for me, probably because I'm a total newbie in C programming. Here's the code:

#include <stdio.h>

char* squeeze(char s[], char c);

main()
{
  printf("%s", squeeze("hello", 'o'));
}

char* squeeze(char s[], char c)
{
  int i, j;

  for(i = j = 0; s[i] != '\0'; i++)
    if(s[i] != c)
      s[j++] = s[i];
    s[j] = '\0';

  return s;
}

It compiles and I get segmentation fault when I run it. I've read th开发者_C百科is faq about about returning arrays and tried the 'static' technique that is suggested there, but still could not get the program working. Could anyone point out exactly what's wrong with it and what should I be paying attention in the future?

The 1st argument passed to the squeeze function is a read-only string literal "hello", which you are trying to modify.

Instead pass it a modifiable char array:

char str[] = "hello";
printf("%s", squeeze(str, 'o'));

The problem is that the constant char array "hello" may not correctly be modified by the function to which it was passed. So, just make sure you're passing a non-constant array (for example by making a local array to be passed, as long as the result is not needed outside of squeeze's caller):

int main()
{
  char xxx[] = "hello";
  printf("%s", squeeze(xxx, 'o'));

  return 0;
}

You'd expect that such a constant could only be passed to a const argument (so that the compiler itself could tell you what you're doing wrong), but, alas, that's not what the C standard mandates (presumably for reasons of backwards compatibility with historical code).

This is trying to modify non-modifiable data.

"hello" is a constant string, stored in memory somewhere. What you're trying to do, then, is change it, and that's generally not allowed. I don't see what you mean by "static", but what you want would be something like...

int main()
{
  char hello_str[16];
  strcpy(hello_str, "hello");
  printf("%s", squeeze(hello_str, 'o'));
}