<:< operator in scala
Can anybody provide some details on <:<
operator in scala.
I think:
if(apple <:< fruit) //checks if apple is a subcl开发者_如何学Pythonass of fruit.
Are there any other explanations? I see many definitions in the scala source file.
The <:<
type is defined in Predef.scala along with the related types =:=
and <%<
as follows:
// used, for example, in the encoding of generalized constraints
// we need a new type constructor `<:<` and evidence `conforms`, as
// reusing `Function2` and `identity` leads to ambiguities (any2stringadd is inferred)
// to constrain any abstract type T that's in scope in a method's argument list (not just the method's own type parameters)
// simply add an implicit argument of type `T <:< U`, where U is the required upper bound (for lower-bounds, use: `U <: T`)
// in part contributed by Jason Zaugg
sealed abstract class <:<[-From, +To] extends (From => To)
implicit def conforms[A]: A <:< A = new (A <:< A) {def apply(x: A) = x} // not in the <:< companion object because it is also intended to subsume identity (which is no longer implicit)
This uses the Scala feature that a generic type op[T1, T2]
can be written T1 op T2
. This can be used, as noted by aioobe, to provide an evidence parameter for methods that only apply to some instances of a generic type (the example given is the toMap
method that can only be used on a Traversable
of Tuple2
). As noted in the comment, this generalizes a normal generic type constraint to allow it to refer to any in-scope abstract type/type parameter. Using this (implicit ev : T1 <:< T2
) has the advantage over simply using an evidence parameter like (implicit ev: T1 => T2
) in that the latter can lead to unintended in-scope implicit values being used for the conversion.
I'm sure I'd seen some discussion on this on one of the Scala mailing lists, but can't find it at the moment.
<:<
is not an operator - it is an identifier and is therefore one of:
- the name of a type (class, trait, type alias etc)
- the name of a method/val or var
In this case, <:<
appears twice in the library, once in Predef
as a class and once as a method on Manifest
.
For the method on Manifest
, it checks whether the type represented by this manifest is a subtype of that represented by the manifest argument.
For the type in Predef
, this is relatively new and I am also slightly confused about it because it seems to be part of a triumvirate of identical declarations!
class <%<[-From, +To] extends (From) ⇒ To
class <:<[-From, +To] extends (From) ⇒ To
class =:=[From, To] extends (From) ⇒ To
I asked around, and this is the explanation I got:
<:<
is typically used as an evidence parameter. For example in TraversableOnce
, toMap
is declared as def toMap[T, U](implicit ev: A <:< (T, U)): immutable.Map[T, U]
. This expresses the constraint that the toMap
method only works if the traversable contains 2-tuples. flatten
is another example. <:<
is used to express the constraint that you can only flatten a traversable of traversables.
Actually, it checks if the class represented by the Manifest
apple is a subclass of the class represented by the manifest fruit.
For instance:
manifest[java.util.List[String]] <:< manifest[java.util.ArrayList[String]] == false
manifest[java.util.ArrayList[String]] <:< manifest[java.util.List[String]] == true
Copy from scala.Predef.scala:
// Type Constraints --------------------------------------------------------------
// used, for example, in the encoding of generalized constraints
// we need a new type constructor `<:<` and evidence `conforms`, as
// reusing `Function2` and `identity` leads to ambiguities (any2stringadd is inferred)
// to constrain any abstract type T that's in scope in a method's argument list (not just the method's own type parameters)
// simply add an implicit argument of type `T <:< U`, where U is the required upper bound (for lower-bounds, use: `U <: T`)
// in part contributed by Jason Zaugg
sealed abstract class <:<[-From, +To] extends (From => To)
implicit def conforms[A]: A <:< A = new (A <:< A) {def apply(x: A) = x}
To better understand the implementation.
sealed abstract class <:<[-From, +To] extends (From => To)
implicit def conforms[A]: A <:< A = new (A <:< A) {def apply(x: A) = x}
I tried to devise a simpler implementation. The following did not work.
sealed class <:<[-From <: To, +To]
implicit def conforms[A <: B, B]: A <:< B = new (A <:< B)
At least because it won't type check in all valid use cases.
case class L[+A]( elem: A )
{
def contains[B](x: B)(implicit ev: A <:< B) = elem == x
}
error: type arguments [A,B] do not conform to class <:<'s
type parameter bounds [-From <: To,+To]
def contains[B](x: B)(implicit ev: A <:< B) = elem == x
^
Hmm... I can't seem to find "<:<" anywhere as well, but "<:" denotes subtyping. From http://jim-mcbeath.blogspot.com/2008/09/scala-syntax-primer.html#types :
List[T] forSome { type T <: Component }
In the above example, we are saying T is some type which is a subtype of Component.
From the sources we have the following explanation:
/**
* An instance of `A <:< B` witnesses that `A` is a subtype of `B`.
* Requiring an implicit argument of the type `A <:< B` encodes
* the generalized constraint `A <: B`.
*
* @note we need a new type constructor `<:<` and evidence `conforms`,
* as reusing `Function1` and `identity` leads to ambiguities in
* case of type errors (`any2stringadd` is inferred)
*
* To constrain any abstract type T that's in scope in a method's
* argument list (not just the method's own type parameters) simply
* add an implicit argument of type `T <:< U`, where `U` is the required
* upper bound; or for lower-bounds, use: `L <:< T`, where `L` is the
* required lower bound.
*
* In part contributed by Jason Zaugg.
*/
@implicitNotFound(msg = "Cannot prove that ${From} <:< ${To}.")
sealed abstract class <:<[-From, +To] extends (From => To) with Serializable
private[this] final val singleton_<:< = new <:<[Any,Any] { def apply(x: Any): Any = x }
// The dollar prefix is to dodge accidental shadowing of this method
// by a user-defined method of the same name (SI-7788).
// The collections rely on this method.
implicit def $conforms[A]: A <:< A = singleton_<:<.asInstanceOf[A <:< A]
@deprecated("Use `implicitly[T <:< U]` or `identity` instead.", "2.11.0")
def conforms[A]: A <:< A = $conforms[A]
/** An instance of `A =:= B` witnesses that the types `A` and `B` are equal.
*
* @see `<:<` for expressing subtyping constraints
*/
@implicitNotFound(msg = "Cannot prove that ${From} =:= ${To}.")
sealed abstract class =:=[From, To] extends (From => To) with Serializable
private[this] final val singleton_=:= = new =:=[Any,Any] { def apply(x: Any): Any = x }
object =:= {
implicit def tpEquals[A]: A =:= A = singleton_=:=.asInstanceOf[A =:= A]
}
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