开发者

Codeigniter active record select, left join, count

I have a form that shows results from a database query, these results can have many other assets ajoined to them and I wanting to find a way of showing how many assets each elemement has. For exam开发者_运维百科ple my table is of areas of england an other table has where the users live I current have this code,

$this->db->select('*');
$this->db->from('places');
$this->db->join('users, places.place_id = user.place_id, left');

$this->db->get();

The issue I am having is getting the query to return the place name and the number of users living in that place, it is possible?


Not knowing your exact db setup, but something like this is how you would do this query using CodeIgniter's Active Record

 $this->db->select('places.place_id');
 $this->db->select_sum('places.place_id', 'total');
 $this->db->from('places');
 $this->db->join('users', 'places.place_id = user.place_id', 'left');
 $this->db->group_by('user.place_id');
 $this->db->get();


select places.place_id,
       count(*) as UsersAtThisPlace
   from
       places,
       users
   where 
       places.place_id = users.place_id
   group by
       places.place_id

Don't know exactly how to implement via your PHP, but it should be as simple as the above query all within your

$this->db->select( "entire string example above" );

Additionally, if you had other descriptive elements from the places table, you could add those as well before the count (just for clarity), but would also have to include them in the group by... such as

select places.place_id,
       places.description,
       places.otherfield,
       count(*) as UsersAtThisPlace
   from
       places,
       users
   where 
       places.place_id = users.place_id
   group by
       places.place_id,
       places.description,
       places.otherfield
0

上一篇:

下一篇:

精彩评论

暂无评论...
验证码 换一张
取 消

最新问答

问答排行榜