How to calculate the number of days between two dates? [duplicate]
I am calculating the number of days between the 'from' and 'to' date. For example, if the from date is 13/04/2010 and the to date is 15/04/2010 the result should be
How do I get the result using JavaScript?
const oneDay = 24 * 60 * 60 * 1000; // hours*minutes*seconds*milliseconds
const firstDate = new Date(2008, 1, 12);
const secondDate = new Date(2008, 1, 22);
const diffDays = Math.round(Math.abs((firstDate - secondDate) / oneDay));
Here is a function that does this:
function days_between(date1, date2) {
// The number of milliseconds in one day
const ONE_DAY = 1000 * 60 * 60 * 24;
// Calculate the difference in milliseconds
const differenceMs = Math.abs(date1 - date2);
// Convert back to days and return
return Math.round(differenceMs / ONE_DAY);
}
Here's what I use. If you just subtract the dates, it won't work across the Daylight Savings Time Boundary (eg April 1 to April 30 or Oct 1 to Oct 31). This drops all the hours to make sure you get a day and eliminates any DST problem by using UTC.
var nDays = ( Date.UTC(EndDate.getFullYear(), EndDate.getMonth(), EndDate.getDate()) -
Date.UTC(StartDate.getFullYear(), StartDate.getMonth(), StartDate.getDate())) / 86400000;
as a function:
function DaysBetween(StartDate, EndDate) {
// The number of milliseconds in all UTC days (no DST)
const oneDay = 1000 * 60 * 60 * 24;
// A day in UTC always lasts 24 hours (unlike in other time formats)
const start = Date.UTC(EndDate.getFullYear(), EndDate.getMonth(), EndDate.getDate());
const end = Date.UTC(StartDate.getFullYear(), StartDate.getMonth(), StartDate.getDate());
// so it's safe to divide by 24 hours
return (start - end) / oneDay;
}
Here is my implementation:
function daysBetween(one, another) {
return Math.round(Math.abs((+one) - (+another))/8.64e7);
}
+<date>
does the type coercion to the integer representation and has the same effect as <date>.getTime()
and 8.64e7
is the number of milliseconds in a day.
Adjusted to allow for daylight saving differences. try this:
function daysBetween(date1, date2) {
// adjust diff for for daylight savings
var hoursToAdjust = Math.abs(date1.getTimezoneOffset() /60) - Math.abs(date2.getTimezoneOffset() /60);
// apply the tz offset
date2.addHours(hoursToAdjust);
// The number of milliseconds in one day
var ONE_DAY = 1000 * 60 * 60 * 24
// Convert both dates to milliseconds
var date1_ms = date1.getTime()
var date2_ms = date2.getTime()
// Calculate the difference in milliseconds
var difference_ms = Math.abs(date1_ms - date2_ms)
// Convert back to days and return
return Math.round(difference_ms/ONE_DAY)
}
// you'll want this addHours function too
Date.prototype.addHours= function(h){
this.setHours(this.getHours()+h);
return this;
}
I have written this solution for another post who asked, how to calculate the difference between two dates, so I share what I have prepared:
// Here are the two dates to compare
var date1 = '2011-12-24';
var date2 = '2012-01-01';
// First we split the values to arrays date1[0] is the year, [1] the month and [2] the day
date1 = date1.split('-');
date2 = date2.split('-');
// Now we convert the array to a Date object, which has several helpful methods
date1 = new Date(date1[0], date1[1], date1[2]);
date2 = new Date(date2[0], date2[1], date2[2]);
// We use the getTime() method and get the unixtime (in milliseconds, but we want seconds, therefore we divide it through 1000)
date1_unixtime = parseInt(date1.getTime() / 1000);
date2_unixtime = parseInt(date2.getTime() / 1000);
// This is the calculated difference in seconds
var timeDifference = date2_unixtime - date1_unixtime;
// in Hours
var timeDifferenceInHours = timeDifference / 60 / 60;
// and finaly, in days :)
var timeDifferenceInDays = timeDifferenceInHours / 24;
alert(timeDifferenceInDays);
You can skip some steps in the code, I have written it so to make it easy to understand.
You'll find a running example here: http://jsfiddle.net/matKX/
From my little date difference calculator:
var startDate = new Date(2000, 1-1, 1); // 2000-01-01
var endDate = new Date(); // Today
// Calculate the difference of two dates in total days
function diffDays(d1, d2)
{
var ndays;
var tv1 = d1.valueOf(); // msec since 1970
var tv2 = d2.valueOf();
ndays = (tv2 - tv1) / 1000 / 86400;
ndays = Math.round(ndays - 0.5);
return ndays;
}
So you would call:
var nDays = diffDays(startDate, endDate);
(Full source at http://david.tribble.com/src/javascript/jstimespan.html.)
Addendum
The code can be improved by changing these lines:
var tv1 = d1.getTime(); // msec since 1970
var tv2 = d2.getTime();
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