next element is (current+1) or 0 (ruby)

I have an interval let's say (0..3) where next element is +1 unless the last. Then the next is 0. I solved it by the code below. Just wondering if there is anything else outhere :-)

def next(max,current)

if current+1 == max
  return 0
else
  return curr开发者_运维技巧ent+1
end  
end

EDIT

please note that when the code runs I need to be able to assign any 'valid number' in my example 0..3 at any time.

Ruby 1.8.7 has Enumerable#cycle

(0..3).cycle{|x| puts x}

will cycle forever.

I think this is really cool:

looper = (0..3).cycle
20.times { puts looper.next }

How about:

def next(max,current)
(current+1) % max
end

Should work unless max==0, but you could easily catch that and bail. :)

Happy coding!

Edit: You should also be aware that next is a reserved keyword (see this overview), it'd be wise to choose another name for your method..