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How can I write an Array in size of char-Pointer in C language [closed]

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I want to get the output like this. The Output is alway like String but it is the result of the Characters. The even Numbers staying like 0 and not changed but the odd Numbers are '+' or '-' and the results are alwas as a chanin Numbers. It can also be Negative Number.Like examples.

How can I write an Array in size of char-Pointer in C language [closed]

I have tried to use calloc and malloc but I don't know how to write it correctly.

2 # include < stdio .h > // fuer printf () 3 # include < stdlib .h > // fuer free 4 5 char * preccalc { char * term [] , int size ); // Description of the Funktion 6 7 int main (int carg , const char ** varg ){ 8 if (( carg ==0)||( carg % 2 != 0)) // even Parameter Number >0 ? 9 return -1; // ( Parameter started with program names ) 10 char * result = preccalc (& varg [1] , carg -1); 11 printf (" Ergebnis :"% s ".\ n",result ); // output 12 free ( result ); 13 return 0; // 0 means it is okay 14 } 15 16 // Ihr Code aus calc.c ab hier

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