Oracle get previous day records
Ok I think I'm getting the previous year instead of the previous day, but I need to previous day.
SELECT TO_DATE(TO_CHAR(CURRENT_DATE, 'YYYY-MM-DD'),'YYYY-MM-DD') - 1 FROM Dual
I'm comparing it to a datetime stamp in this format and wish to get all the rows from the previous day.
YYYY-MM-DD HH:MM:SS
So I'm trying something like this
开发者_如何学JAVASELECT field,datetime_field
FROM database
WHERE datetime_field > TO_DATE(TO_CHAR(CURRENT_DATE, 'YYYY-MM-DD'),'YYYY-MM-DD') - 1
how about sysdate?
SELECT field,datetime_field
FROM database
WHERE datetime_field > (sysdate-1)
You can remove the time part of a date by using TRUNC
.
select field,datetime_field
from database
where datetime_field >= trunc(sysdate-1,'DD');
That query will give you all rows with dates starting from yesterday. Note the second argument to trunc()
. You can use this to truncate any part of the date.
If your datetime_fied contains '2011-05-04 08:23:54'
, the following date will be returned
trunc(datetime_field, 'HH24') => 2011-05-04 08:00:00
trunc(datetime_field, 'DD') => 2011-05-04 00:00:00
trunc(datetime_field, 'MM') => 2011-05-01 00:00:00
trunc(datetime_field, 'YYYY') => 2011-00-01 00:00:00
SELECT field,datetime_field
FROM database
WHERE datetime_field > (CURRENT_DATE - 1)
Its been some time that I worked on Oracle. But, I think this should work.
this
SELECT field,datetime_field
FROM database
WHERE datetime_field > (sysdate-1)
will work. The question is: is the 'datetime_field' has the same format as sysdate ? My way to handle that: use 'to_char()' function (only works in Oracle).
samples: previous day:
select your_column
from your_table
where to_char(sysdate-1, 'dd.mm.yyyy')
or
select extract(day from date_field)||'/'||
extract(month from date_field)||'/'||
extract(year from date_field)||'/'||
as mydate
from dual(or a_table)
where extract(day from date_field) = an_int_number and
extract(month from date_field) = an_int_number and so on..
comparing date:
select your_column
from your_table
where
to_char(a_datetime_column, 'dd.mm.yyyy') > or < or >= or <= to_char(sysdate, 'dd.mm.yyyy')
time range between yesterday and a day before yesterday:
select your_column
from your_table
where
to_char(a_datetime_column, 'dd.mm.yyyy') > or < or >= or <= to_char(sysdate-1, 'dd.mm.yyyy') and
to_char(a_datetime_column, 'dd.mm.yyyy') > or < or >= or <= to_char(sysdate-2, 'dd.mm.yyyy')
other time range variation
select your_column
from your_table
where
to_char(a_datetime_column, 'dd.mm.yyyy') is between to_char(sysdate-1, 'dd.mm.yyyy')
and to_char(sysdate-2, 'dd.mm.yyyy')
Simple solution and understanding
To answer the question:
SELECT field,datetime_field
FROM database
WHERE TO_CHAR(date_field, 'YYYYMMDD') = TO_CHAR(SYSDATE-1, 'YYYYMMDD');
Some explanation
If you have a field that is not in date format but want to compare using date i.e. field is considered as date but in number format e.g. 20190823 (YYYYMMDD)
SELECT * FROM YOUR_TABLE WHERE ID_DATE = TO_CHAR(SYSDATE-1, 'YYYYMMDD')
If you have a field that is in date/timestamp format and you need to compare, Just change the format
SELECT TO_CHAR(SYSDATE-1, 'YYYY-MM-DD HH24:MI:SS') FROM DUAL
IF you want to return it to date format
SELECT TO_DATE(TO_CHAR(SYSDATE-1, 'YYYY-MM-DD HH24:MI:SS'), 'YYYY-MM-DD HH24:MI:SS') AS NEW_DATE FROM DUAL
Conclusion.
With this knowledge you can convert the filed you want to compare to a YYYYMMDD or YYYY-MM-DD or any year-month-date format then compare with the same sysdate format.
I think you can also execute this command:
select (sysdate-1) PREVIOUS_DATE from dual;
Im a bit confused about this part "TO_DATE(TO_CHAR(CURRENT_DATE, 'YYYY-MM-DD'),'YYYY-MM-DD')". What were you trying to do with this clause ? The format that you are displaying in your result is the default format when you run the basic query of getting date from DUAL. Other than that, i did this in your query and it retrieved the previous day 'SELECT (CURRENT_DATE - 1) FROM Dual'. Do let me know if it works out for you and if not then do tell me about the problem. Thanks and all the best.
精彩评论