Check if last characters of an NSString are numbers

Is it possible to see of a string ends with a number which length is not known?

1. "String 1" -> 1
2. "String 开发者_如何转开发4356" -> 4356
3. "String" -> nil

If so, how can I determine that number?

To test that a string ends with numbers, you can use an NSPredicate, such as:

NSPredicate endsNumerically = [NSPredicate predicateWithFormat:@"SELF matches %@", @"\\d+$"];
[endsNumerically evaluateWithObject:string]; // returns TRUE if predicate succeeds

NSScanner is sometimes useful for extracting things from strings, but it doesn't scan backward. You could define a Gnirts (reverse string) class and use that with an NSScanner, but that's probably more hassle than it's worth.

NSString's rangeOfCharacterFromSet:options:, which I had hope to use, only looks for a single character (it's like strchr and strrchr, if you're familiar with C), but we can roll our own that returns a contiguous range of characters from a set (a little like strspn) as a category on NSString. While we're at it, let's include methods that return substrings rather than ranges.

RangeOfCharacters.h:

@interface NSString (RangeOfCharacters)
/* note "Characters" is plural in the methods. It has poor readability, hard to 
 * distinguish from the rangeOfCharacterFromSet: methods, but it's standard Apple 
 * convention.
 */
-(NSRange)rangeOfCharactersFromSet:(NSCharacterSet*)aSet;
-(NSRange)rangeOfCharactersFromSet:(NSCharacterSet*)aSet options:(NSStringCompareOptions)mask;
-(NSRange)rangeOfCharactersFromSet:(NSCharacterSet*)aSet options:(NSStringCompareOptions)mask range:(NSRange)range;

// like the above, but return a string rather than a range
-(NSString*)substringFromSet:(NSCharacterSet*)aSet;
-(NSString*)substringFromSet:(NSCharacterSet*)aSet options:(NSStringCompareOptions)mask;
-(NSString*)substringFromSet:(NSCharacterSet*)aSet options:(NSStringCompareOptions)mask range:(NSRange)range;
@end

RangeOfCharacters.m:

@implementation NSString (RangeOfCharacters)
-(NSRange)rangeOfCharactersFromSet:(NSCharacterSet*)aSet {
    return [self rangeOfCharactersFromSet:aSet options:0];
}

-(NSRange)rangeOfCharactersFromSet:(NSCharacterSet*)aSet options:(NSStringCompareOptions)mask {
    NSRange range = {0,[self length]};
    return [self rangeOfCharactersFromSet:aSet options:mask range:range];
}

-(NSRange)rangeOfCharactersFromSet:(NSCharacterSet*)aSet options:(NSStringCompareOptions)mask range:(NSRange)range {
    NSInteger start, curr, end, step=1;
    if (mask & NSBackwardsSearch) {
        step = -1;
        start = range.location + range.length - 1;
        end = range.location-1;
    } else {
        start = range.location;
        end = start + range.length;
    }
    if (!(mask & NSAnchoredSearch)) {
        // find first character in set
        for (;start != end; start += step) {
            if ([aSet characterIsMember:[self characterAtIndex:start]]) {
#ifdef NOGOTO
                break;
#else
                // Yeah, a goto. If you don't like them, define NOGOTO.
                // Method will work the same, it will just make unneeded
                // test whether character at start is in aSet
                goto FoundMember;
#endif
            }
        }
#ifndef NOGOTO
        goto NoSuchMember;
#endif
    }
    if (![aSet characterIsMember:[self characterAtIndex:start]]) {
    NoSuchMember:
        // no characters found within given range
        range.location = NSNotFound;
        range.length = 0;
        return range;
    }

FoundMember:
    for (curr = start; curr != end; curr += step) {
        if (![aSet characterIsMember:[self characterAtIndex:curr]]) {
            break;
        }
    }
    if (curr < start) {
        // search was backwards
        range.location = curr+1;
        range.length = start - curr;
    } else {
        range.location = start;
        range.length = curr - start;
    }
    return range;
}

-(NSString*)substringFromSet:(NSCharacterSet*)aSet {
    return [self substringFromSet:aSet options:0];
}

-(NSString*)substringFromSet:(NSCharacterSet*)aSet options:(NSStringCompareOptions)mask  {
    NSRange range = {0,[self length]};
    return [self substringFromSet:aSet options:mask range:range];
}
-(NSString*)substringFromSet:(NSCharacterSet*)aSet options:(NSStringCompareOptions)mask range:(NSRange)range {
    NSRange range = [self rangeOfCharactersFromSet:aSet options:mask range:range];
    if (NSNotFound == range.location) {
        return nil;
    }
    return [self substringWithRange:range]; 
}
@end

To use the new category to check that a string ends with digits or to extract the number:

NSString* number = [string substringFromSet:[NSCharacterSet decimalDigitCharacterSet] 
                             options:NSBackwardsSearch|NSAnchoredSearch];
if (number != nil) {
    return [number intValue];
} else {
    // string doesn't end with a number.
}

Lastly, you can use a third party regular expression library, such as RegexKit or RegexkitLite.

I couldn't get the NSPredicate code above to work correctly, though it looks like it should. Instead I accomplished the same thing with

if ([string rangeOfString:@"\\d+$" options:NSRegularExpressionSearch].location != NSNotFound) {
    // string ends with a number
}

Hat-tip to this answer.