linux ps aux command [closed]

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How obtain the running process with absolute path name from ps command

13598 ?        Ssl    0:00 /opt/something --run-id 2 -n /home/laks/f1 -l l.log
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I need the output as -

/opt/something --run-id 2 -n /home/laks/f1 -l l.log

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If i understand the question correctly, just use awk.

ps aux | awk '{print $11}'

Otherwise just do man awk and look at the field separator.

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Using user-defined format in ps:

ps xa -o cmd

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Okay I got the answer ,

cat /proc/13598/cmdline

HTH

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which `ps aux | cut -c 66- | cut -d\  -f 1`

will list absolute paths of all of the processes, you could work with that.